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[英]How to get the Highest, then the lowest, then the 2nd higest, and then the 2nd lowest value and so on from a table
[英]How to get the 2nd highest from a table where it need to be added first in sql server in a single query?
面试中有人问我这个问题,这张桌子
Roll | Sub | Marks
1 A 20
1 B 21
2 A 15
2 B 19
3 A 21
3 B 22
现在我必须找到该卷并获得该学生获得的第二高分
所以我回答了这个:
declare @trytable table
(
roll int,
total int
)
insert @trytable
select Roll, SUM(Marks)
from Student
group by Roll
Select *
from @trytable t
where t.total in (select MAX(total) from @trytable where total not in ( select
MAX(total) from @trytable))
这给出了正确的答案,但访问员希望通过不使用表变量在单个查询中完成此操作
结果应该是
Roll | Total Marks
1 41
所以我该怎么做...请让我知道
下面的查询给出了将两个主题标记相加得出的第二高分的卷数。
SELECT TOP 1 Roll, Marks
FROM
(
SELECT DISTINCT TOP 2 Roll,
SUM(Marks) over (Partition by Roll) Marks
FROM
YourTable
ORDER BY marks DESC
) temp
ORDER BY Marks
要么
SELECT
DISTINCT Roll,
Marks,
SRANK
FROM
(
SELECT
Roll,
Marks,
DENSE_RANK() OVER( ORDER BY Marks DESC) AS SRANK
FROM
(
SELECT
Roll,
SUM(Marks) over (Partition by Roll) Marks
FROM YourTable
)x
)x
WHERE SRANK=2
如果我对您的理解正确,那么您只想获取第二高的学生的总成绩,而该学生是否按成绩进行识别? 如果是这样的话:
select roll, sum(Marks) from Student group by roll order by total limit 1,1;
不是100%知道1,1-您所说的是,我只想要1行,而不是第一行。
也可以通过简单的查询来完成:
select Marks from trytable where N = (select count(distinct Marks) from trytable b where a.Marks <= b.Marks)
where N = any value
要么
SELECT Roll,Marks
FROM tableName WHERE Marks =
(SELECT MIN(Marks ) FROM
(SELECT TOP (2) Marks
FROM tableName
ORDER BY Marks DESC) )
您可以使用RowNumber()之类的分析函数
select * from
(Select t.*, RowNumber() over (order by Total desc) as rownum from trytable )
where rownum = 2
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