PHP Oracle oci_num_rows结果0

Question

我对Oracle中的查询有疑问：

问题是， oci_num_rows的结果始终为0。

到目前为止，这是我的代码：

  $query = "SELECT IP_ADDRESS, STATUS FROM SEIAPPS_IP_ADDRESS WHERE IP_ADDRESS='$ip'";
  $result = oci_parse($c1, $query);
  oci_execute($result);
  echo $found = oci_num_rows($result);

为确保确定，我尝试清除条件"WHERE IP_ADDRESS='$ip'" 。 结果仍然是0，而我的表中有一些数据。

有什么建议吗？

Answer 1

用这个：

$query = "SELECT IP_ADDRESS, STATUS FROM SEIAPPS_IP_ADDRESS WHERE IP_ADDRESS='$ip'";
$result = oci_parse($c1, $query);
oci_execute($result);
$numrows = oci_fetch_all($result, $res);
echo $numrows." Rows";

Answer 2

此函数不返回选择的行数！ 对于SELECT statements此函数将返回通过oci_fetch*()函数提取到缓冲区的行数。

尝试执行此操作以检查您的连接凭据是否正确。

<?php
$conn = oci_connect("hr", "welcome", "localhost/XE");
if (!$conn) {
    $e = oci_error();   // For oci_connect errors do not pass a handle
    trigger_error(htmlentities($e['message']), E_USER_ERROR);
}
?>

Answer 3

对于陷入此陷阱的其他人，这是oci_fetch_all方法将返回的内容的简单摘要。

$s = oci_parse($conn, "
          SELECT 1 AS A FROM DUAL 
    UNION SELECT 2 AS A FROM DUAL 
    UNION SELECT 3 AS A FROM DUAL 
    UNION SELECT 4 AS A FROM DUAL
");
oci_execute($s);
echo "records fetched: ". oci_num_rows($s)."\n";

oci_fetch($s);
echo "records fetched: ". oci_num_rows($s)."\n";

oci_fetch($s);
echo "records fetched: ". oci_num_rows($s)."\n";

oci_fetch_all($s, $out);
echo "records fetched: ". oci_num_rows($s)." out count: ". count($out['A']) . "\n";

将输出：

records fetched: 0
records fetched: 1
records fetched: 2
records fetched: 4 out count: 2

因此oci_num_rows是增量的，每次对oci_fetch调用都会使计数器增加一（假设至少oci_fetch_all获取一条记录），而oci_fetch_all将获取所有剩余的行并将其放入$out缓冲区。