如何在MySQL条件下将表与其自身进行比较

Question

嗨，我需要一些帮助，我有一张桌子出售如下..我想将其与自身进行比较，并显示结果，其中公司不应该等于公司，价格应该等于price..i我在mysql中尝试了很多查询，但是没有得到理想的结果，请帮助我！ 告诉正确的查询将非常感谢你们！

sells(company,drink,price)

查询我试过

mysql>'select company,drink,price from sells JOIN s ON(price=price1) where (comp
any1!=company);'

s是sells的副本表

+----------------+----------------+-------+
| company        | drink          | price |
+----------------+----------------+-------+
| PepsiCo        | Mirinda        |    45 |
| PepsiCo        | Pepsi          |    45 |
| Coca-Cola      | Coca-cola zero |    45 |
| Nestle         | Nescafe        |    35 |
| Nestle         | Nescafe        |    35 |
| Nestle         | Nescafe        |    35 |
| Nestle         | Nescafe        |    35 |
| Nestle         | Nescafe        |    35 |
| Nestle         | Nescafe        |    35 |
| Coca-Cola      | Coca-cola zero |    45 |
| Shezan         | Twister        |    25 |
| Nestle         | Fruita vitals  |    25 |
| Murree Brewery | Big Apple      |    35 |
| Murree Brewery | Big Lemon      |    35 |
| Murree Brewery | Big Orange     |    35 |
| Murree Brewery | Peach Malt     |    35 |
| Murree Brewery | Lemon Malt     |    35 |
| Murree Brewery | Apple Malt     |    35 |
+----------------+----------------+-------+

Answer 1

尝试这个？

SELECT T1.company, T2.company, T1.price 
FROM sells T1 
JOIN sells T2
WHERE 
T1.company != T2.company
AND
T1.price = T2.price
GROUP BY T1.company, T1.price;