[英]How get count element in query select with Distinct?
SELECT DISTINCT
t1.name as t1_name,
t1.unit as t1_unit,
t1.id_producer_goods AS hi_id_producer_goods,
t2.name as t2_name
FROM Table1 t1
left join Table2 t2 on t1.id_web_site=t2.id_web_site
WHERE t1.id='23'
如何获取计数t1.name
在它查询?
我检查代码:
SELECT DISTINCT
t1.name as t1_name,
count(t1.name) as count,
t1.unit as t1_unit,
t1.id_producer_goods AS hi_id_producer_goods,
t2.name as t2_name
FROM Table1 t1
left join Table2 t2 on t1.id_web_site=t2.id_web_site
WHERE t1.id='23'
但它的代码有错误:
Column 'Table1.name' is invalid in the select list because
it is not contained in either an aggregate function or the GROUP BY clause.
我知道我在行count(t1.name) as count,
写的不是count(t1.name) as count,
但是如何得到正确的计数t1.name
?
PS:查询获取具有唯一行t1.name, t1.unit, t1.id_producer_goods, t2.name
。 计数t1.name
应显示每个元素t1.name
所有计数。
你必须添加
GROUP BY t1.name,t1.unit,hi.id_producer_goods,t2.name
每当您沿其他列使用聚合函数时,您必须为其余列添加group by子句。
对于这些你可以删除不同的。 Group by将为您完成。
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