[英]Android: Error parsing data and cannot be converted to JSONObject
[英]Error Parsing Data - String cannot be converted to JSONObject
我想通过 Web-Service 访问 Android 应用程序。 在 Web 服务中执行新的注册。 在 android 应用程序中,新注册的 xml 文件已生成。 数据成功保存在SQL服务器数据库中,并通过Web服务正确保存并以jason字符串返回数据。 但是当字符串转换为 JSONObject 时,它给了我这样的错误:
Error parsing data org.json.JSONException: Value [{"userid":105,"created_at":"03-Oct-2013","success":1,"email":"rty@gmail.com","password":"rty12345","name":"rtyu"}] of type org.json.JSONArray cannot be converted to JSONObject
我已将活动注册为 RegisterActivity.java
else
{
erName.setText("");
erPass.setText("");
erEmail.setText("");
erCopass.setText("");
UserFunction userFunction = new UserFunction();
JSONObject json = userFunction.registerUser(name, email, password);
// check for login response
try {
if (json.getString(KEY_SUCCESS) != null) {
String res = json.getString(KEY_SUCCESS);
if(Integer.parseInt(res) == 1){
// user successfully registred
// Store user details in SQLite Database
Databasehandler db = new Databasehandler(getApplicationContext());
JSONObject json_user = json.getJSONObject("user");
// Clear all previous data in database
userFunction.logoutUser(getApplicationContext());
db.addUser(json_user.getString(KEY_NAME), json_user.getString(KEY_EMAIL),
json.getString(KEY_UID), json_user.getString(KEY_CREATED_AT));
// Launch Dashboard Screen
Intent login = new Intent(getApplicationContext(), LoginActivity.class);
// Close all views before launching Dashboard
login.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
startActivity(login);
// Close Registration Screen
Toast.makeText(RegisterActivity.this,"You are Registered successfully",Toast.LENGTH_SHORT).show();
finish();
}else{
// Error in registration
Toast.makeText(RegisterActivity.this,"User Allready Registered!!!",Toast.LENGTH_LONG).show();
}
}
} catch (JSONException e) {
e.printStackTrace();
}
}
}
});
因为错误发生在该行:
if (json.getString(KEY_SUCCESS) != null)
在 JSONParser 类中,jObj 获取空值。 问题出在这一行: jObj = new JSONObject(json);
JSONParser 类的代码:
public class JSONParser {
static InputStream is = null;
static JSONObject jObj = null;
static String json = "";
// constructor
public JSONParser() {
}
public JSONObject getJSONFromUrl(String url, List<NameValuePair> params) {
// Making HTTP request
try {
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
httpPost.setEntity(new UrlEncodedFormEntity(params));
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "n");
}
is.close();
json = sb.toString();
Log.e("JSON", json);
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
// try parse the string to a JSON object
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
// return JSON String
return jObj;
}
}
其中服务调用的另一类 UserFunction : public class UserFunction {
private JSONParser jsonParser;
// Testing in localhost using wamp or xampp
// use http://10.0.2.2/ to connect to your localhost ie http://localhost/
private static String loginURL = "http://192.168.1.120/rvAndroidServices.ashx";
private static String registerURL = "http://192.168.1.120/rvAndroidServices.ashx";
private static String name1 = "http://192.168.1.120/rvAndroidServices.ashx";
private static String login_tag = "login";
private static String register_tag = "register";
private static String name_tag = "name";
// constructor
public UserFunction(){
jsonParser = new JSONParser();
}
/**
* function make Login Request
* @param email
* @param password
* */
public JSONObject loginUser(String email, String password){
// Building Parameters
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("tag", login_tag));
params.add(new BasicNameValuePair("email", email));
params.add(new BasicNameValuePair("password", password));
jsonParser= new JSONParser();
JSONObject json = jsonParser.getJSONFromUrl(loginURL, params);
// return json
// Log.e("JSON", json.toString());
return json;
}
/**
* function make Login Request
* @param name
* @param email
* @param password
* */
public JSONObject registerUser(String name, String email, String password){
// Building Parameters
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("tag", register_tag));
params.add(new BasicNameValuePair("name", name));
params.add(new BasicNameValuePair("email", email));
params.add(new BasicNameValuePair("password", password));
jsonParser = new JSONParser();
// getting JSON Object
JSONObject json = jsonParser.getJSONFromUrl(registerURL, params);
// return json
return json;
}
/**
* Function get Login status
* */
public boolean isUserLoggedIn(Context context){
Databasehandler db = new Databasehandler(context);
int count = db.getRowCount();
if(count > 0){
// user logged in
return true;
}
return false;
}
public String getAppCategorydetail(Context context){
Databasehandler db = new Databasehandler(context);
String count = db.getAppCategorydetail();
return count;
}
/**
* Function to logout user
* Reset Database
* */
public boolean logoutUser(Context context){
Databasehandler db = new Databasehandler(context);
db.resetTables();
return true;
}
public JSONObject chname(String name)
{
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("tag", name_tag));
params.add(new BasicNameValuePair("name", name));
JSONObject json = jsonParser.getJSONFromUrl(name1, params);
return json;
}
}
在响应字符串中,你得到的是 jsonArray 而不是 JsonObject,所以当你说
try {
jObj = new JSONObject(json);
}
这里 json 需要转换成 JsonArray 而不是 JSONObject。 之后从 json 数组中获取第一个对象。
类似的东西:
try {
JSONArray jArr = new JSONArray(json);
JSONObject jObj = jArr.getJSONObject(0);
}
希望这有帮助!
Error parsing data org.json.JSONException: Value [{"userid":105,"created_at":"03-Oct-2013","success":1,"email":"rty@gmail.com","password":"rty12345","name":"rtyu"}] of type org.json.JSONArray cannot be converted to JSONObject
你的例外向你解释一切
你的 String 是JSONArray not JSONObject
你需要从JSONArray
获取JSONObject
。
所以使用JSONArray
来获取JSONOBbject
更改为:
jObj = new JSONArray(json).getJSONObject(0);
试试这个...
JSONArray data = jsonObj.getJSONArray("data");
如果 apis 是用 php 编写的,那么您的 Web 服务(apis)很可能不会将数据返回为“json” - 尝试在下面添加一行
header('内容类型:应用程序/json');
它应该工作。
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