[英]Google BigQuery SQL for summing individual columns
我正在寻找一种高效的(ish)BigQuery SQL查询来解决以下问题:
我有一张桌子,看起来像这样:
Row | Col_A | Col_B |
---------------------
1 | 2 | 3 |
2 | 1 | 4 |
3 | 5 | 7 |
4 | 2 | 3 |
5 | 6 | 1 |
...and so on (>million rows)
每列的值是一个范围为[1..7]的ID。
该查询应产生以下内容,即对每一列的每个代码求和:
Code | Total Col_A | Total Col_B
--------------------------------
1 | 1 | 0
2 | 2 | 0
3 | 0 | 2
4 | 0 | 1
5 | 1 | 0
6 | 1 | 0
7 | 0 | 1
有人知道在BigQuery中执行此操作而不使用多个SELECT的方法吗?
干杯。
您可以使用样本数据创建公共数据集吗? 编写适用于您的数据的查询并验证结果将更加容易。
开始查询:
SELECT Code, COUNT(Col_A) count_column_x, COUNT(Col_B) count_column_y
FROM [your:list.of_codes] a
LEFT JOIN EACH [your:sample.table] b
ON a.Code=b.Col_A
GROUP BY 1
(这并不完美,如果您共享一张桌子可以使用,它将走得更远)
有人知道在BigQuery中执行此操作而不使用多个SELECT的方法吗?
使用标准SQL进行一次SELECT
#standardSQL
WITH logs AS (
SELECT 2 AS Col_A, 3 AS Col_B UNION ALL
SELECT 1 AS Col_A, 4 AS Col_B UNION ALL
SELECT 5 AS Col_A, 7 AS Col_B UNION ALL
SELECT 2 AS Col_A, 3 AS Col_B UNION ALL
SELECT 6 AS Col_A, 1 AS Col_B
)
SELECT
id,
SUM(CAST(id = Col_A AS INT64)) AS Total_Col_A,
SUM(CAST(id = Col_B AS INT64)) AS Total_Col_B
FROM logs, UNNEST(GENERATE_ARRAY(1,7)) AS id
GROUP BY id
ORDER BY id
或使用COUNTIF()
#standardSQL
WITH logs AS (
SELECT 2 AS Col_A, 3 AS Col_B UNION ALL
SELECT 1 AS Col_A, 4 AS Col_B UNION ALL
SELECT 5 AS Col_A, 7 AS Col_B UNION ALL
SELECT 2 AS Col_A, 3 AS Col_B UNION ALL
SELECT 6 AS Col_A, 1 AS Col_B
)
SELECT
id,
COUNTIF(id = Col_A) AS Total_Col_A,
COUNTIF(id = Col_B) AS Total_Col_B
FROM logs, UNNEST(GENERATE_ARRAY(1,7)) AS id
GROUP BY id
ORDER BY id
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