如何确定复合键中的列位置

Question

我需要确定数据库中的所有主键。 以下代码似乎可以很好地完成此工作：

SELECT i.name AS IndexName,
   OBJECT_NAME (ic.OBJECT_ID) AS TableName,
   COL_NAME (ic.OBJECT_ID, ic.column_id) AS ColumnName
FROM sys.indexes AS i
   INNER JOIN sys.index_columns AS ic
      ON i.OBJECT_ID = ic.OBJECT_ID AND i.index_id = ic.index_id
WHERE i.is_primary_key = 1

我的问题是某些键是复合键。 此查询标识哪些键是复合键（sys.indexes表中特定indexName的多行），但未显示顺序。 我需要知道这一点，因为：

PRIMARY KEY CLUSTERED 
(
[bl_id] ASC,
[fl_id] ASC,
[rm_id] ASC
)

与以下内容不同：

PRIMARY KEY CLUSTERED 
(
[rm_id] ASC
[fl_id] ASC,
[bl_id] ASC,

）

Answer 1

key_ordinal似乎可以解决问题：

SELECT i.name AS IndexName,
   OBJECT_NAME (ic.OBJECT_ID) AS TableName,
   COL_NAME (ic.OBJECT_ID, ic.column_id) AS ColumnName,
   ic.Key_ordinal as ColumnOrder
FROM sys.indexes AS i
   INNER JOIN sys.index_columns AS ic
      ON i.OBJECT_ID = ic.OBJECT_ID AND i.index_id = ic.index_id
WHERE i.is_primary_key = 1
ORDER BY ic.OBJECT_ID, ic.Key_ordinal