繁体   English   中英

在PHP查询中使用MSSQL STUFF

[英]Using MSSQL STUFF in query with PHP

因此,首先让我解释一下我要做什么,然后我要如何做,然后是问题出在哪里。 我正在尝试创建mssql查询以从数据库中读取发票。 每张发票本质上都是按发票ID分组在一起的单个费用的汇总。 结果是,不同的费用可能来自不同的容器(费用与容器相关)。 我需要做的是按发票ID对费用进行分组,并用诸如“ |”之类的分隔符来连接发票中所有费用的容器名称。 我创建了一个临时表@t,其中包含生成发票所需的所有费用和容器名称。 在网上寻找了一段时间之后,我发现了STUFF命令,该命令似乎可以执行我想要的操作(出现并执行)。 所以这是我查询的SQL:

select invoice_id, [Total Paid] RefNumCount,PayCount, MIN([rowNumber]) as rowNumber,     Vendor, Due, [Invoice Number], Company, MAX(Location) as Location,
 SUM([Funded Amount]) as [Funded Amount], 
 [Company ID], [Invoice ID], provider_reference_number, reconcile_date, all_providers
, STUFF(
        (
        select '|' + t1.[Container Name]
        from @t t1
        where t1.[Invoice Number] = t.[Invoice Number]
        order by t1.[Container Name]
        for XML PATH(''), TYPE
        ).value('.', 'nvarchar(100)')
        ,1,1,''
     ) as [Container Name] 

from @t t
group by invoice_id, [Total Paid], RefNumCount, PayCount, Vendor, Due, [Invoice Number], Company, 
    [Company ID], [Invoice ID], provider_reference_number, reconcile_date, all_providers

当我运行的是SQL Server Management Studio 2008时,它运行得很好。 但是,当我在PHP应用程序中使用此代码时,查询不起作用,并且最终由于尝试读取空结果集而导致致命错误。 有人知道为什么会发生此问题吗? 或者,如果还有另一种串联字符串的方法?

以下是用于调用查询的PHP代码段

           try{
                $q = cms_database::instance();
                 $result = $q->query($sql_statement);        
                 if (!$result) {
                       throw new Exception("Database Error [{$q->errno}] {$q->error}");
                  } 

                $invoices = array();
                while($row=$result->fetch_assoc()) {
                    $invoiceX = array();
                    $invoiceX["rowNum"]     = $row["rowNumber"];
                    $invoiceX["Vendor"]     = $row["Vendor"];
                    $invoiceX["Due"]        = $row["Due"];
                    $invoiceX["Acct"]       = $row["Container Name"];//$row["Account Number"];
                    $invoiceX["container_id"]=$row["container_id"];
                    $invoiceX["provider_id"] =$row["provider_id"];
                    $invoiceX["Invoice"]    = $row["Invoice Number"];
                    $invoiceX["Location"]   = $row["Company"];
                    $invoiceX["FundedAmt"]  = $row["Funded Amount"];
                    $invoiceX["InvoiceID"]  = $row["Invoice ID"];
                    $invoiceX["Notes"]      = $row["Notes"];
                    //merge the notes with notes from payment history that matches the invoiceid


                    $invoices[] = $invoiceX;
                }

                //filter out invoices with all reference numbers accounted for and remaining to be paid is $0.00



                $returnPackage["data"] = $invoices;
                //print $result;
            } catch (Exception $e){
                $returnPackage["success"]=0;
                $returnPackage["message"]=$e.message;

            }

我得到的错误是:
致命错误 :在第116行的D:[path_to_the_file] .php中的非对象上调用成员函数fetch_assoc()

第116行是代码行

while($row=$result->fetch_assoc()) {

尽管这可能会晚一点,但是请尝试使用此SQL调用。

select invoice_id, [Total Paid] RefNumCount,PayCount, MIN([rowNumber]) as rowNumber, 
       Vendor, Due, [Invoice Number], Company, MAX(Location) as Location,
       SUM([Funded Amount]) as [Funded Amount], [Company ID], [Invoice ID],
       provider_reference_number, reconcile_date, all_providers , 
       STUFF((select '|' + t1.[Container Name]
              from @t t1
              where t1.[Invoice Number] = t.[Invoice Number]
              order by t1.[Container Name]
              for XML PATH('')),1,1,'') as [Container Name] 
from @t t
group by invoice_id, [Total Paid], RefNumCount, PayCount, Vendor, Due, [Invoice Number], 
         Company, [Company ID], [Invoice ID], provider_reference_number, reconcile_date, 
         all_providers

当您添加“ |”时发生错误 在下面的select语句中,它将剥离xml标记,当您使用.value()尝试提取数据时会导致错误。

STUFF((select '|' + ... from ... for XML PATH(''), TYPE).value('.', 'nvarchar(100)'),1,1,'')

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM