[英]How do you create an element programmatically from a data template defined in XAML?
[英]Can you display the first element of a ListBox rather than create a data template for xaml
以下绑定是基于IEnumerable的活动。 问题是,在我的xaml中...我只想输出数组中的第一个元素。 您可以按照以下方式做些什么:
<Run Text="{Binding activity[0].created_by.name}"></Run>
还是必须为活动IEnumerable数组链接另一个数据模板?
这是ActivityStream类的属性(我现在注意到它是一个List..hmm。)
...
[DataMember]
public List<object> activity { get; set; }
...
这是我在哪里做PropertyChanged yada yada的东西
public IEnumerable<JamesStream> activityStream;
...
private async void LoadActivityStreamSection()
{
activityStreamRepository = new JamesStreamRepository();
var tempActivityStream = await activityStreamRepository.GetAllBySpaceId(space.space_id);
activityStream = tempActivityStream;
ActivityStream = null;
//The Activitiy Stream has a property which is of type List<object> called activity
// In my xaml I just want to be outputting the 1st entry of the List<object> property .created_by_name
}
public event PropertyChangedEventHandler PropertyChanged;
protected virtual void OnPropertyChanged([CallerMemberName] string propertyName = null)
{
PropertyChangedEventHandler tempEvent = PropertyChanged;
if (tempEvent != null)
{
// property changed
tempEvent(this, new PropertyChangedEventArgs(propertyName));
}
}
public IEnumerable<JamesStream> ActivityStream
{
get
{
return activityStream;
}
set
{
if (activityStream != value)
{
OnPropertyChanged();
}
}
}
如果您的IEnumerable具有.First属性,您是否可以附加到该属性?
您的代码正常工作... :)。
您能说明如何填写您的收藏吗? 我认为这可能是因为您没有触发INotifyPropertyChanged(或类似INotify的集合)事件
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