在C ++中调用函数时我的程序崩溃

Question

因此我必须执行三个功能：一个询问公司里有多少员工，另一个询问他们错过了多少天，第三个询问平均员工人数除以缺少的天数。我所要做的就是使用cout提示并调用函数。我不确定我是否做对了，但是在计算平均值时会崩溃。

#include <iostream>
#include <iomanip>
using namespace std;

int employee(int employeeNum);
int missingDays(int daysMissing);
double getAvg(int employeeNum,int daysMissing,double average);

int employee(int employeeNum)
{
  cout<<"Enter the number of employee in the company.";
  cin>>employeeNum;
  return employeeNum;
}

int missingDays(int daysMissing)
{
  cout<<"Enter the amount of days employees missed during the past year.";
  cin>>daysMissing;
  return daysMissing;
}

double getAvg(int employeeNum,int daysMissing,double average)
{
  average=employeeNum/daysMissing;
  return average;
}

int main()
{
  int employeeNum,people,missing,daysMissing;
  double avg,average;

  people=employee(employeeNum);
  cout<<"The number of employees in the company is "<<people<<"."<<endl;

  missing=missingDays(daysMissing);
  cout<<"The number of days employees missed during the past year is "<<missing<<".";

  avg=getAvg(employeeNum,daysMissing,average);
  cout<<average;
}

让我知道我该怎么做，并感谢您的帮助。

Answer 1

这看起来像是家庭作业，因此您只需要轻推即可。 因此，请注意以下几点：为什么您的函数employee()和missingDays()接受参数？ 为什么getAvg()需要3？ 您的输入值最终包含哪些变量？ 接下来将在哪里使用它们（如果有的话）？

Answer 2

你的问题是这条线

missing=missingDays(daysMissing);

由于某些原因，您有两个变量“ daysMissing”（我不确定为什么首先将其传递给missingDays函数）

在该行之后， missing将包含值输入，而不是daysMissing （因为它没有通过引用传递）

您的getAvg函数可能因零除错误而崩溃。

Answer 3

因此，取决于编译器， daysMissing的值是未定义的或使用0初始化的。

在函数getAvg您将employeeNum/daysMissing;划分employeeNum/daysMissing;

但是您不可以被零除，就这样:)

Answer 4

#include <iostream>
#include <iomanip>
using namespace std;

int employee(int employeeNum);
int missingDays(int daysMissing);
double getAvg(int employeeNum,int daysMissing,double average);

int employee(int employeeNum)
{
  cout<<"Enter the number of employee in the company: ";
  cin>>employeeNum;
  return employeeNum;
}

int missingDays(int daysMissing)
{
  cout<<"Enter the amount of days employees missed during the past year: ";
  cin>>daysMissing;
  return daysMissing;
}

double getAvg(int employeeNum,int daysMissing)
{
    if(daysMissing == 0)
    {
        return 0;
    }
  return (double)employeeNum/daysMissing;;
}

int main()
{
  int employeeNum,people,missing,daysMissing;
  double avg,average;

  people=employee(employeeNum);
  cout<<"The number of employees in the company is: "<<people<<"\n";

  missing=missingDays(daysMissing);
  cout<<"The number of days employees missed during the past year is: "<<missing<<"\n";

  avg=getAvg(people,missing);
  cout<<avg;
}