[英]Spring MVC @RequestBody receive an Object wrapper with non-primitive attributes
我按如下方式创建JSON:
var manager = {
username: "admin",
password: "admin"
};
var userToSubscribe = {
username: "newuser",
password: "newpassword",
email: "user@1and1.es"
};
var openid = "myopenid";
var subscription = {
manager: manager,
userToSubscribe : userToSubscribe,
openid : openid
};
$.ajax({
url: '/myapp/rest/subscribeUser.json',
type: 'POST',
dataType: 'json',
contentType: 'application/json',
mimeType: 'application/json',
data: JSON.stringify({subscription : subscription})
});
这是发送的JSON:
{"subscription":{"manager":{"username":"admin","password":"admin"},"userToSubscribe":{"username":"newuser","password":"newpassword","email":"user@1and1.es"},"openid":"myopenid"}}
我想将这个JSON映射到Wrapper类。 这是包装器:
private class Subscription{
private User manager;
private User userToSubscribe;
private String openid;
public User getManager() {
return manager;
}
public void setManager(User manager) {
this.manager = manager;
}
public User getUserToSubscribe() {
return userToSubscribe;
}
public void setUserToSubscribe(User userToSubscribe) {
this.userToSubscribe = userToSubscribe;
}
public String getOpenid() {
return openid;
}
public void setOpenid(String openid) {
this.openid = openid;
}
}
pom.xml中的jackson依赖项(我使用的是spring 3.1.0.RELEASE):
<dependency>
<groupId>org.codehaus.jackson</groupId>
<artifactId>jackson-mapper-asl</artifactId>
<version>1.9.10</version>
</dependency>
rest-servlet.xml中的映射
<bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
<property name="messageConverters">
<list>
<ref bean="jsonConverter" />
</list>
</property>
</bean>
<bean id="jsonConverter" class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter">
<property name="supportedMediaTypes" value="application/json" />
</bean>
以及控制器方法的标题:
public @ResponseBody SimpleMessage subscribeUser(@RequestBody Subscription subscription)
作为POST的结果,我收到400不正确的请求错误。 是否可以这样做或者我是否需要使用@RequestBody
String或@RequestBody Map<String,Object>
并自己解码JSON?
谢谢!
看着你的JSON
{
"subscription": {
"manager": {
"username": "admin",
"password": "admin"
},
"userToSubscribe": {
"username": "newuser",
"password": "newpassword",
"email": "user@1and1.es"
},
"openid": "myopenid"
}
}
根元素是subscription
,它是一个JSON对象。 您的Subscription
类没有subscription
字段。 因此,没有任何内容可以将subscription
元素映射到它,因此它会因400 Bad Request而失败。
创建一个类SubscriptionWrapper
public class SubscriptionWrapper {
private Subscription subscription;
public Subscription getSubscription() {
return subscription;
}
public void setSubscription(Subscription subscription) {
this.subscription = subscription;
}
}
并更改您的处理程序方法以接受此类型的参数
public @ResponseBody SimpleMessage subscribeUser(@RequestBody SubscriptionWrapper subscriptionWrapper)
您可能需要在MappingJacksonHttpMessageConverter
配置ObjectMapper
(您应该使用MappingJackso2nHttpMessageConverter
,因此它会忽略缺少的属性)。
我要回答我自己的问题。 首先要特别感谢Sotirios Delimanolis,因为他给了我钥匙以便调查它发生了什么。
如您所知,我从视图中创建了以下json:
{"manager":{"username":"admin","password":"admin"},"userToSubscribe":{"username":"newuser","password":"newpassword","email":"user@1and1.es"},"openid":"https://myopenid..."}
我稍微改变了一下,因为我意识到创建对象Subscription和var Subscription不是必需的。 如果您像这样构建JSON,它将完美地工作:
var manager = {
username: "admin",
password: "admin"
};
var userToSubscribe = {
username: "newuser",
password: "newpassword",
email: "user@1and1.es"
};
var openid = "https://myopenid...";
$.ajax({
url: '/dp/rest/isUserSuscribed.json',
type: 'POST',
dataType: 'json',
contentType: 'application/json',
mimeType: 'application/json',
data: JSON.stringify({manager : manager, userToSubscribe : userToSubscribe, openid : openid})
});
控制器收到这个json:
@RequestMapping(method=RequestMethod.POST, value="/isUserSuscribed.json")
public @ResponseBody ResponseMessageElement<Boolean> isUserSuscribed(@RequestBody SubscriptionWrapper subscription){
和SubscriptionWrapper ......
private static class SubscriptionWrapper {
BasicUser manager;
BasicUser userToSubscribe;
String openid;
public BasicUser getManager() {
return manager;
}
public void setManager(BasicUser manager) {
this.manager = manager;
}
public BasicUser getUserToSubscribe() {
return userToSubscribe;
}
public void setUserToSubscribe(BasicUser userToSubscribe) {
this.userToSubscribe = userToSubscribe;
}
public String getOpenid() {
return openid;
}
public void setOpenid(String openid) {
this.openid = openid;
}
}
那么......问题是什么? 我收到了错误的请求400错误...我调试了MappingJackson2HttpMessageConverter作为Sotirios建议并且有一个异常(没有合适的构造函数)。 Jackson Mapping无法构建内部类,无论此类是否不是静态的。 将SubscriptionWrapper设置为static是解决我的问题的方法。
您还可以查看以下答案: http://stackoverflow.com/questions/8526333/jackson-error-no-suitable-constructor
: http://stackoverflow.com/questions/8526333/jackson-error-no-suitable-constructor
http://stackoverflow.com/questions/12139380/how-to-convert-json-into-pojo-in-java-using-jackson
如果你有反序列化的问题,请检查: http://stackoverflow.com/questions/17400850/is-jackson-really-unable-to-deserialize-json-into-a-generic-type
: http://stackoverflow.com/questions/17400850/is-jackson-really-unable-to-deserialize-json-into-a-generic-type
感谢所有的答复。
你不需要自己做这件事。 您需要在pom中添加此依赖项:
<dependencies>
<dependency>
<groupId>org.codehaus.jackson</groupId>
<artifactId>jackson-mapper-asl</artifactId>
<version>1.8.5</version>
</dependency>
</dependencies>
之后春天会为你做转换。
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