[英]I keep getting a null pointer exception
我正在制作一个图书馆程序,该程序会记录馆藏中的所有书籍以及每本书的副本数。 这是代码
import java.util.Arrays;
import java.util.Scanner;
public class Library{
static String title;
static String author;
static int id;
static int copies;
static String date;
static Book[] database = new Book[100];
static int count=0;
public static void main(String[] args){
int i;
Scanner s = new Scanner(System.in);
do{
addBook();
System.out.println("would you like to add another book?");
i=s.nextInt();
}while(i == 0);
database[0].viewDetails();
database[1].viewDetails();
checkingOut();
}
public static void addBook(){
Scanner s = new Scanner(System.in);
System.out.println("Enter the title of the book you want to add to the collection");
title=s.nextLine();
System.out.println("Enter the author of the book you want to add to the collection");
author=s.nextLine();
System.out.println("Enter the publishing date of the book you want to add to the collection");
date=s.nextLine();
System.out.println("Enter the ID number of the book you want to add to the collection");
id=s.nextInt();
System.out.println("Enter the the number of copies that will be added into the collection");
copies=s.nextInt();
Book Book1 = new Book(date, author, copies, id, title);
database[count] = Book1;
count++;
}
public static void checkingOut(){
boolean found=false;
int idSearch;
int i=0;
Scanner s = new Scanner(System.in);
System.out.println("Enter the ID number of the book you want to check out");
idSearch=s.nextInt();
while(i<database.length && found!=true){
if(database[i].getIdentificationNumber() == idSearch){
found = true;
}
i++;
}
if(found==true){
database[i].checkOut();
System.out.println("There are "+database[i].getNumberCopies()+" copies left");
}
else{System.out.println("There is no book with that ID number!");}
}
}
我在检出方法的第55行收到空指针异常,我不知道为什么。 请让我知道,如果您能发现它有什么帮助,将不胜感激。
因为赋值的表达式返回分配的值 ,所以将始终执行if(found=true)
,这将导致database[i].checkOut();
在不应该执行的地方执行。
您应该写:
if(found)
这就是为什么在比较boolean
s时避免写==
的原因。 编写if(someBoolean)
足够了。
发现==真,未发现=真
应该是if(found==true)
代替=
使用==
as =
将始终评估为true
。
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