[英]Little help needed with C Code
您好,我正在研究带有单个IR传感器的线路跟随器机器人。
已为我提供了模拟客户端+硬件。 我现在正在尝试模拟部分,其中必须沿着有效路径移动机器人,直到在迷宫中找到令牌为止。 然后停下来,给出坐标x,y,就像这样:“在x,y上找到令牌”。 服务器应用程序基于全局坐标系(例如东,西...)给出的坐标具有一个局部坐标系(例如,左,右,前...)。 在启动时选择机器人的方向,并在屏幕上显示实际坐标。 在将所有动作发送到服务器应用程序之前,在屏幕上给出对机器人方向的必要校正(“向左”,“向前”,“向右”,“转身”),然后将坐标发送给服务器。 示例:欢迎来到Sim机器人,在交叉点:3,5上,方向为:向南机器人移动:向左机器人前进:4,5 ...在以下位置找到令牌:2,1
有两种方法可以在本地或在远程服务器上模拟程序,在本地计算机上我可以看到迷宫,但是在远程服务器上总是会给我未知的迷宫。
我有两个C档案
roboproxy.c
#include <stdarg.h>
#include "../h/RobotProxy.h"
/// initialized with ROBOT_FAIL
int currentIntersection = ROBOT_FAIL;
#if !defined(vasprintf)
static int vasprintf(char **s, const char *format, va_list ap) {
/* Guess we need no more than 100 bytes. */
int n, size = 100;
va_list save_ap;
if ((*s = (char*) malloc(size)) == NULL)
return -1;
while (1) {
/* work on a copy of the va_list because of a bug
in the vsnprintf implementation in x86_64 libc
*/
#ifdef __va_copy
__va_copy(save_ap, ap);
#else
save_ap = ap;
#endif
/* Try to print in the allocated space. */
#ifdef _vsnprintf
n = _vsnprintf(*s, size, format, save_ap);
#else
n = vsnprintf(*s, size, format, save_ap);
#endif
va_end(save_ap);
/* If that worked, return the string. */
if (n > -1 && n < size) {
return n;
}
/* Else try again with more space. */
if (n > -1) { /* glibc 2.1 */
size = n + 1; /* precisely what is needed */
} else { /* glibc 2.0 */
size *= 2; /* twice the old size */
}
if ((*s = (char*) realloc(*s, size)) == NULL) {
return -1;
}
}
}
#endif
#if !defined(asprintf)
static int asprintf(char **s, const char *format, ...) {
va_list vals;
int result;
va_start(vals, format);
result = vasprintf(s, format, vals);
va_end(vals);
return result;
}
#endif
/// Set the robot to the specified position
/// @ returns ROBOT_SUCCESS, ROBOT_FAIL or ROBOT_TOKENFOUND
int Robot_Move(int x, int y) {
char* buffer;
asprintf(&buffer, "{\"x\":%d,\"y\":%d}", x, y);
char* query = url_encode(buffer);
free(buffer);
char* response = sendAndRecieve(concat(URL, query));
if (response == NULL) {
puts("Connection to server failed!");
return ROBOT_FAIL;
}
if (contains(response, "\"code\":1")) {
puts("Connection declined!");
return ROBOT_FAIL;
}
if (contains(response, "\"code\":2")) {
puts("Connection blocked!");
return ROBOT_FAIL;
}
if (contains(response, "\"code\":3")) {
printf("Invalid position! (x=%d, y=%d)\n", x, y);
return ROBOT_FAIL;
}
int foundIntersection = 0;
bool token = false;
if (contains(response, "\"north\":true"))
foundIntersection |= D_N;
if (contains(response, "\"east\":true"))
foundIntersection |= D_E;
if (contains(response, "\"south\":true"))
foundIntersection |= D_S;
if (contains(response, "\"west\":true"))
foundIntersection |= D_W;
if (contains(response, "\"token\":true"))
token = true;
free(query);
currentIntersection = foundIntersection;
if (token)
return ROBOT_TOKENFOUND;
return ROBOT_SUCCESS;
}
/// Get the intersections of the current node that the robot is at
/// @ returns always the intersection at position x=0,y=0 if Robot_Move was not called first
int Robot_GetIntersections() {
if (currentIntersection == ROBOT_FAIL)
Robot_Move(0, 0);
return currentIntersection;
}
客户端软件
#include "../h/Configuration.h"
int main(void) {
printf("Token: %d\n", Robot_Move(1, 0));
printf("Intersection: %d\n", Robot_GetIntersections());
return EXIT_SUCCESS;
}
当我在控制台中运行程序时,它给我Token为1,然后在找到任何令牌后将变为2。
因此在roboclientsim.c中,我添加了“
If (Robot_Move()==2) //as Robot_move is returning the %d value for Token
printf("another token found ");
“
但是我的编译器给出的问题是robot_move很少有人争论,
谁能帮我解决这个问题?
Robot_Move
接受2个参数:
int Robot_Move(int x, int y);
而且您可以毫无争议地调用它。
If (Robot_Move()==2)
那是错误。 我怀疑您想做的是:
int main(void) {
int token = Robot_Move(1, 0);
printf("Token: %d\n", token);
printf("Intersection: %d\n", Robot_GetIntersections());
if (token == 2)
printf("another token found ");
return EXIT_SUCCESS;
}
或者可能:
int main(void) {
int token = Robot_Move(1, 0);
if (token == 2) {
printf("Token: %d\n", token);
printf("Intersection: %d\n", Robot_GetIntersections());
} else {
printf("another token found ");
}
return EXIT_SUCCESS;
}
检查方法int Robot_Move(int x, int y)
的原型。调用它时需要提供2个参数。
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