[英]Upload Image Using Ajax and PHP and Return Uploaded Image URL
我试图不刷新就上传图像,但是我对ajax的了解不多。 我使用ajax函数提交帖子时,有php文件,您的返回图像URL。
使用Javascript
$(document).ready(function() {
$('#photoimg').live('change', function() {
$("#preview").html('');
$("#preview").html('<img src="loader.gif" alt="Uploading...."/>');
$("#imageform").ajaxForm({
target: '#preview'
}
}).submit();
});
});
PHP
<?php
$path = "uploads/";
$valid_formats = array("jpg", "png", "gif", "bmp");
if(isset($_POST) and $_SERVER['REQUEST_METHOD'] == "POST")
{
$name = $_FILES['photoimg']['name'];
$size = $_FILES['photoimg']['size'];
if(strlen($name))
{
list($txt, $ext) = explode(".", $name);
if(in_array($ext,$valid_formats))
{
if($size<(1024*1024))
{
$actual_image_name = time().substr(str_replace(" ", "_", $txt), 5).".".$ext;
$tmp = $_FILES['photoimg']['tmp_name'];
if(move_uploaded_file($tmp, $path.$actual_image_name))
{
$imge1="uploads/".$actual_image_name;
echo $imge1;
}
else
echo "failed";
}
else
echo "Image file size max 1 MB";
}
else
echo "Invalid file format..";
}
else
echo "Please select image..!";
exit;
}
?>
HTML
<form id="imageform" method="post" enctype="multipart/form-data" action='ajaximage.php'>
Upload your image <input type="file" name="photoimg" id="photoimg" />
</form>
<div id='preview'>
</div>
<img src = "" id="thumb_img" />
现在结果是图像URL。 当图像选择ajax自动将沙子发布到php.Php保存图像并返回url且此url显示在目标div中。 像图像一样选择target
div背景变化。
我会做类似的事情:
$('#myForm').ajaxForm(function(url) {
$('#preview').css('background-image', "url(" + url + ")");
});
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