无法将jsbin演示转换为小提琴

Question

我知道这听起来很奇怪，但是此演示http://jsbin.com/ixUzURUB/1/edit我无法将其转换为http://jsfiddle.net/jhb2L/我在做什么错？ 谢谢。

 google.load("visualization", "1", {packages:["corechart"]});
  google.setOnLoadCallback(drawChart);
  function drawChart() {
    var data = google.visualization.arrayToDataTable([
      ['Task', 'Hours per Day'],
      ['Work',     11],
      ['Eat',      2],
      ['Commute',  2],
      ['Watch TV', 2],
      ['Sleep',    7]
    ]);

    var options = {
      title: 'My Daily Activities'
    };

    var chart = new google.visualization.PieChart(document.getElementById('piechart'));
    chart.draw(data, options);
  }

Answer 1

当您添加未以.js结尾的外部资源时，JSFiddle就会出现问题。 在路径中添加了？fake = .js，它可以正常工作。 还删除了window.onload = function() {}; JSFiddle添加的内容，现在似乎可以正常工作。

http://jsfiddle.net/jhb2L/3/

Answer 2

尝试粘贴此代码，它应该可以工作：

<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script type="text/javascript">
  google.load("visualization", "1", {packages:["corechart"]});
  google.setOnLoadCallback(drawChart);
  function drawChart() {
    var data = google.visualization.arrayToDataTable([
      ['Task', 'Hours per Day'],
      ['Work',     11],
      ['Eat',      2],
      ['Commute',  2],
      ['Watch TV', 2],
      ['Sleep',    7]
    ]);

    var options = {
      title: 'My Daily Activities'
    };

    var chart = new google.visualization.PieChart(document.getElementById('piechart'));
    chart.draw(data, options);
  }
</script>

<div id="piechart" style="width: 900px; height: 500px;"></div>