[英]How can you pass an array in a POST with Spring RestTemplate?
我使用Spring的RestTemplate在POST中传递数组时遇到了困难。 以下是我使用的代码:
我在这里调用RestTemplate:
private static void sendEntries() {
RestTemplate restTemplate = new RestTemplate();
String uri = "http://localhost:8080/api/log/list.json";
// Both LogEntry and ExceptionEntry extend Entry
LogEntry entry1 = new LogEntry();
ExceptionException entry2 = new ExceptionEntry();
Entry[] entries = {entry1, entry2};
entries = restTemplate.postForObject(uri, entries, Entry[].class);
System.out.println(new Gson().toJson(entries));
}
控制器包含:
@RequestMapping(value = "api/log/list", method = RequestMethod.POST)
public @ResponseBody Entry[] saveList(@RequestBody Entry[] entries) {
for (Entry entry : entries) {
entry = save(entry);
}
return entries;
}
这导致:
org.springframework.web.client.HttpClientErrorException: 400 Bad Request
它看起来不像是将数组添加到请求中。 当我不尝试传递数组时,所有其他POST请求都有效。 我只是不确定我需要做什么才能使数组正确传递。
这是正确的做法吗? 是否可以通过集合?
你可以查看这篇文章: 如何使用Spring RestTemplate将List或String数组传递给getForObject,该帖子的解决方案是:
列表或其他类型的对象可以使用RestTemplate的postForObject方法发布。 我的解决方案如下:
控制器:
@RequestMapping(value="/getLocationInformations", method=RequestMethod.POST)
@ResponseBody
public LocationInfoObject getLocationInformations(@RequestBody RequestObject requestObject)
{
// code block
}
创建一个发布到服务的请求对象:
public class RequestObject implements Serializable
{
public List<Point> pointList = null;
}
public class Point
{
public Float latitude = null;
public Float longitude = null;
}
创建响应对象以从服务获取值:
public class ResponseObject implements Serializable
{
public Boolean success = false;
public Integer statusCode = null;
public String status = null;
public LocationInfoObject locationInfo = null;
}
使用请求对象发布点列表并从服务获取响应对象:
String apiUrl = "http://api.website.com/service/getLocationInformations";
RequestObject requestObject = new RequestObject();
// create pointList and add to requestObject
requestObject.setPointList(pointList);
RestTemplate restTemplate = new RestTemplate();
ResponseObject response = restTemplate.postForObject(apiUrl, requestObject, ResponseObject.class);
// response.getSuccess(), response.getStatusCode(), response.getStatus(), response.getLocationInfo() can be used
如何POST数组:
private String doPOST(String[] array) {
RestTemplate restTemplate = new RestTemplate(true);
//add array
UriComponentsBuilder builder = UriComponentsBuilder.fromHttpUrl("https://my_url");
for (String item : array) {
builder.queryParam("array", item);
}
//another staff
String result = "";
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.MULTIPART_FORM_DATA);
HttpEntity<LinkedMultiValueMap<String, Object>> requestEntity =
new HttpEntity<>(headers);
ResponseEntity<String> responseEntity = restTemplate.exchange(
builder.build().encode().toUri(),
HttpMethod.POST,
requestEntity,
String.class);
HttpStatus statusCode = responseEntity.getStatusCode();
if (statusCode == HttpStatus.ACCEPTED) {
result = responseEntity.getBody();
}
return result;
}
POST请求将具有下一个结构:
POST https://my_url?array=your_value1&array=your_value2
在服务器端:
public class MyServlet extends HttpServlet {
@Override
public void doPost(HttpServletRequest req, HttpServletResponse response) {
try {
String[] array = req.getParameterValues("array");
String result = doStaff(array);
response.getWriter().write(result);
response.setStatus(HttpServletResponse.SC_ACCEPTED);
} catch (Exception e) {
response.setStatus(HttpServletResponse.SC_BAD_REQUEST);
}
}
}
试试这个例子
更改您的请求映射
@RequestMapping(value = "/train", method = RequestMethod.POST)
至
@RequestMapping(value = "/train/{category}/{positiveDocId[]}/{negativeDocId[]}", method = RequestMethod.GET)
和restTemplate中的URL
以下面给出的格式更改URl
http://localhost:8080/admin/train/category/1,2,3,4,5/6,7,8,9
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