在通用方法中传递/指定属性？

Question

我试图将我写的一些代码移动到更通用的方法。 虽然方法较长，但我遇到问题的部分如下：

public static void Test()

{    
           MyObjectType[] list1 = ListMyObjectTypeMethod1();
            MyObjectType[] list2 = ListMyObjectTypeMethod2();

            List<MyObjectType> linqAblelist1 = new List<MyObjectType>(list1);
            List<MyObjectType> linqAblelist2 = new List<MyObjectType>(list2);

            IEnumerable<MyObjectType> toBeAdded = linqAblelist1.Where(x => linqAblelist2.All(y => y.Property1 != x.Property1));
            IEnumerable<MyObjectType> toBeDeleted = linqAblelist2.Where(a => linqAblelist1.All(b => b.Property1 != a.Property1));

}

我试图为MyObjectType传递一个泛型类型，但我在哪里[如何在这里设置属性？]如何在方法的参数中指定？

public static void Test<T>(T[] x, T[] y)
        {
            List<T> list1 = new List<T>(x);
            List<T> list2 = new List<T>(y);
            IEnumerable<T> toBeAdded = list1.Where(x => list2.All(y => y.[How To Set Property Here?] != x.[How To Set Property Here?]));
            IEnumerable<T> toBeDeleted = list2.Where(a => list1.All(b => b.[How To Set Property Here?])); != a.[How To Set Property Here?]));));

        }

Answer 1

将选中的属性作为Func<T, TProperty>传递：

public static void Test<T, TProperty>(T[] x, T[] y, Func<T, TProperty> propertySelector)
    {
        List<T> list1 = new List<T>(x);
        List<T> list2 = new List<T>(y);
        IEnumerable<T> toBeAdded = list1.Where(x => list2.All(y => !propertySelector(y).Equals(propertySelector(x))));
        IEnumerable<T> toBeDeleted = list2.Where(a => !list1.All(b => propertySelector(b).Equals(propertySelector(a))));

    }

然后，您可以通过为propertySelector指定lambda表达式来调用它：

Test(someArray, someOtherArray, t => t.SomeProperty);

Answer 2

最好的选择是引入泛型类型约束，以确保T继承自特定类或实现接口。 在任何一种情况下，类或接口都必须声明Property1 。 像这样：

public static void Test<T>(T[] x, T[] y) where T : IHasProperty1
{
    …
}

Answer 3

您需要对泛型类型设置一些约束。

public static void Test<T>(T[] x, T[] y) where T : <SomeInterface>
{
   List<T> list1 = new List<T>(x);
   List<T> list2 = new List<T>(y);
   IEnumerable<T> toBeAdded = list1.Where(x => list2.All(y => y.PropertyName != x.PropertyName));
    IEnumerable<T> toBeDeleted = list2.Where(a => list1.All(b => b.PropertyName)); != a.PropertyName));));

}

Answer 4

您可以添加一个通用约束，以确保T具有您期望的属性。 就像是：

public static void Test<T>(T[] x, T[] y) where T : MyObjectType
{
    List<T> list1 = new List<T>(x);
    List<T> list2 = new List<T>(y);
    IEnumerable<T> toBeAdded = list1.Where(x => list2.All(y => y.Property1  != x.Property1 ));
    IEnumerable<T> toBeDeleted = list2.Where(a => list1.All(b => b.Property1 )); != a.[How To Set Property Here?]));));

}