PHP多语言网站错误问题

Question

我是php的新手，我试图用php创建一个简单的多语言网站。 在下面提到了我的全部代码，我总共拥有四个文件，index.php，setlocal.php，以及在该en.php和fn.php文件中的一个文件夹语言环境。 具有这样的文件夹结构。

----  
index.php  
setlocal.php  

locale  
 en.php  
 fn.php

文件代码是..

的index.php

<?php  
include_once "setlocal.php";  
?>  

<!doctype html>  
<head>  
<title><?php echo $GLOBALS['l']['title1']; ?></title>  
</head>  
<body>  

<ul class="header-nav pull-right">  
<li><a href="index.php?lang=en">English</a></li>  
<li><a href="index.php?lang=fn">French</a></li>  
</ul>  

<p><?php echo $GLOBALS['l']['homdes1']; ?></p>  

</body>  
</html>

setlocal.php

<?php  

($language = @$_GET['lang']) or $language = 'en';  

$allowed = array('en', 'te');  

if(!in_array($language, $allowed)) {  
$language = 'en';  
}  

include "locale/{$language}.php";  

$GLOBALS['l'] = '$local';  

?>

地区
|
zh.php

<?php  

$local = array (  
'title1' => 'sample english content',  
'homdes1' => 'sample english contentsample english contentsample english content');  

?>

fn.php

<?php  

$local = array (  
'title1' => 'sample french content',  
'homdes1' => 'sample french contentsample french contentsample french contentsample       french contentsample french content');  

?>

在运行代码时，它显示如下错误，请帮助我解决此问题，谢谢。

Warning: Illegal string offset 'homdes1' in  D:\madhu_new\korimerla\htdocs\korimerla\php\index.php on line 15  
$

Answer 1

尝试从setlocal.php文件的这一行中删除$local周围的引号：

$GLOBALS['l'] = '$local';

这样它显示为：

$GLOBALS['l'] = $local;

这将为您提供：

// you can use var_dmp() this to see what you have in $GLOBALS['l']
var_dump($GLOBALS['l']);

array(2) {
  ["title1"]=>
  string(22) "sample english content"
  ["homdes1"]=>
  string(66) "sample english contentsample english contentsample english content"
}

然后可以使用数组语法进行访问：

echo $GLOBALS['l']['homdes1'];

// gives:    
sample english contentsample english contentsample english content

Answer 2

将您的setlocal.php更改为此：

<?php  

//Check if $_GET['lang'] is set, if not default to 'en'
$language = isset($_GET['lang']) ? $_GET['lang'] : 'en';

$allowed = array('en', 'te');  

if(!in_array($language, $allowed)) {  
  $language = 'en';  
}  

include "locale/$language.php";  

//without single quotes. PHP will expand (convert) variable names inside double quotes to the value, but within single vars are printed as is.
$GLOBALS['l'] = $local; 

?>

PHP多语言网站错误问题

问题描述

2 个解决方案

解决方案1
1 已采纳 2013-11-28 01:57:53

解决方案2
0 2013-11-28 02:01:15

PHP多语言网站错误问题

问题描述

2 个解决方案

解决方案1 1 已采纳 2013-11-28 01:57:53

解决方案2 0 2013-11-28 02:01:15

解决方案1
1 已采纳 2013-11-28 01:57:53

解决方案2
0 2013-11-28 02:01:15