MySQL WHERE结果基于先前的WHERE子句

Question

抱歉，如果有一种简单的Mysql方法可以做到这一点，但是我发现很难说出任何有意义的搜索结果。

我正在搜索我的网站，并且搜索工作正常，直到我尝试通过基于下拉菜单中所选流派的单词来搜索它。

此查询最能代表我要执行的操作：

SELECT *
FROM Books
JOIN bookauthor ON books.BookID = bookauthor.BookID 
JOIN authors ON bookauthor.AuthorID = authors.AuthorID 
JOIN bookgenre ON books.BookID = bookgenre.BookID 
JOIN genre ON bookgenre.GenreID = genre.GenreID 
WHERE genre.Genre = 'Fantasy' 
WHERE books.BookName LIKE '%$variable%' OR authors.Forename LIKE '%$variable%' OR authors.Surname LIKE '%$variable%' 
GROUP BY books.BookName ORDER BY authors.AuthorID

我想选择所有已选择类型的书籍，然后从它们中进行其他检查，因为现在具有OR的功能会覆盖其他检查，并且最终会吐出每条记录。

我猜想我可能必须有一个查询来选择所有类型的书籍，然后运行另一个查询以从该上一个查询中进行选择。 只有我从未做过，我需要将其合并到我的搜索功能中...

这是我当前的搜索代码，与尝试搜索选择了“全部”以外的流派的东西时效果很好，如果您只选择一个流派而不输入任何内容，那么它将显示该流派的书，只是如果您选择还要输入搜索词。

if(isset($_POST['search']))
            {
                if($_POST['genre']!="All")
                    {
                    $where3 = "WHERE genre.GenreID = '".$_POST['genre']."'";        
                    }
                if($_POST['field'] == "All")
                    {
                        if(str_word_count($_POST['find'])>=2)
                        {
                        $findEx = explode(' ', $_POST['find']);
                        $where2 = "OR authors.Forename LIKE  '%".($findEx[0])."%' AND authors.Surname LIKE  '%".$findEx[1]."%'";
                        }
                    $where = "
                    WHERE books.BookName LIKE  '%".($_POST['find'])."%'
                    OR  authors.Forename LIKE  '%".($_POST['find'])."%' OR authors.Surname LIKE  '%".($_POST['find'])."%'
                    $where2
                    ";
                    }
                else if($_POST['field'] == "Books")
                    {
                    $where = "WHERE books.BookName LIKE  '%".($_POST['find'])."%'";
                    }
                else if($_POST['field'] == "Authors")
                    {
                    if(str_word_count($_POST['find'])>=2)
                        {
                        $findEx = explode(' ', $_POST['find']);
                        $where = "WHERE authors.Forename LIKE  '%".($findEx[0])."%' AND authors.Surname LIKE  '%".$_POST[1]."%'";
                        }
                    else
                        {
                        $where = "WHERE authors.Forename LIKE  '%".($_POST['find'])."%' OR authors.Surname LIKE  '%".($_POST['find'])."%'";
                        }
                    }                       
                    $sql = "SELECT * FROM Books
                        JOIN bookauthor ON books.BookID        = bookauthor.BookID
                        JOIN authors    ON bookauthor.AuthorID = authors.AuthorID
                        JOIN bookgenre  ON books.BookID        = bookgenre.BookID
                        JOIN genre      ON bookgenre.GenreID   = genre.GenreID
                        ".$where3."
                        ".$where."
                        GROUP BY books.BookName                                
                        ORDER BY authors.AuthorID"; 
                        echo $sql;
            }

我对这一切仍然很陌生，因此很抱歉，如果我的搜索代码看起来像一场噩梦，尽管可以接受任何提示，但它用最少的代码即可满足我的需求。

感谢所有帮助-汤姆

Answer 1

也许

SELECT *
FROM Books
JOIN bookauthor ON books.BookID = bookauthor.BookID 
JOIN authors ON bookauthor.AuthorID = authors.AuthorID 
JOIN bookgenre ON books.BookID = bookgenre.BookID 
JOIN genre ON bookgenre.GenreID = genre.GenreID 
WHERE genre.Genre = 'Fantasy' 
AND books.BookName LIKE '%$variable%' (OR authors.Forename LIKE '%$variable%' OR authors.Surname LIKE '%$variable%') 
GROUP BY books.BookName ORDER BY authors.AuthorID