如何将PHP Web服务连接到SQL Server 2008 R2

Question

我们正在开发php webservice，我们的数据库在sql server 2008 r2上

/ * sql连接字符串* /

     $link = mssql_connect('localhost','usrname','pass') or die('Cannot connect to the DB');     
     mssql_select_db('Data Source=PC-NAME;Initial Catalog=DBNAME.MDF;Persist Security Info=True',$link) or die('Cannot select the DB');

        /* grab the posts from the db */

        echo $query = "SELECT * FROM add_product WHERE prod_pos = '".$_GET['prod_pos']."'";
        $result = mssql_query($query,$link) or die('Errant query:  '.$query);

它在mssql_connect上给出致命错误。

致命错误：在第11行的service.php中调用未定义的函数mssql_connect（）

那么如何将php web服务与sql server 2008 r2连接起来呢？

提前致谢...

Answer 1

您将需要从Microsoft下载并安装sqlsrv扩展名。 在此处查找一个选项： http : //www.microsoft.com/zh-cn/download/details.aspx?id=20098

请注意，该扩展名不再称为“ mssql”，而是现在为“ sqlsrv”，因此您将要使用sqlsrv_connect()等。

Answer 2

得到答案..............

    <?php
        $number_of_posts = $_GET['prod_pos']; 

        $format = 'json';

        /* connect to the db */

        $serverName = "(local)";

        /* Get UID and PWD from application-specific files.  */
        $uid = "usrname of sql server 2008";
        $pwd = "password";
        $connectionInfo = array( "UID"=>$uid, "PWD"=>$pwd, "Database"=>"db name" );

        /* Connect using SQL Server Authentication. */
        $conn = sqlsrv_connect( $serverName, $connectionInfo);
        if( $conn === false )
        {
             echo "Unable to connect.</br>";
             die( print_r( sqlsrv_errors(), true));
        }


        /* Query SQL Server for the login of the user accessing the database. */

        $tsql = "SELECT * FROM add_product WHERE prod_pos='".$number_of_posts."'";
        $stmt = sqlsrv_query( $conn, $tsql);
        if( $stmt === false )
        {
             echo "Error in executing query.</br>";
             die( print_r( sqlsrv_errors(), true));
        }


        /* create one master array of the records */

        $posts = array();
        while($post = sqlsrv_fetch_array($stmt) ) 
        {
                $posts[] = array('post'=>$post);
        }


        /* output in necessary format */

         if($format == 'json') 
         {
            header('Content-type: application/json');
            echo json_encode(array('posts'=>$posts));
         }

        /* disconnect from the db */

        $stmt = null; 
        $conn = null; 

     ?>

使用php成功连接到sql server 2008 r2数据库