[英]Identifying percentage in Fact Table
我是编程新手,找不到答案。
我有以下尺寸(表)和事实表:
我必须具有以下报告: HomeRegion , Hour , RegionName , UserPercentage 。
如示例中所示,上午9点,只有3.67%的家庭区域是A的人迁移到B。
我应该创建一个类似的。
问题是获取ig UserPercentage。 这是我到目前为止所做的代码。
SELECT c.HomeRegion, mt.myhour as Time, r.RegionName as CurrentRegion,
(SELECT COUNT(*)
/*number of users who move from their home
region to CurrentRegion at specific time*/
)/COUNT(c.CustomerId)*100 as UserPercentage
FROM dbo.FactTable ft
inner join dbo.Customer c
ON ft.CustomerId = c.CustomerId
inner join dbo.myTime mt
ON ft.TimeId = mt.ID
inner join dbo.Regions r
ON ft.RegionId = r.RegionId
WHERE mt.myhour = '09'
GROUP BY c.HomeRegion, mt.myhour, r.RegionName
ORDER BY c.HomeRegion, r.RegionName
在您的评论区域尝试类似的方法。
SELECT (TMP1.Count*100)/COUNT(TMP2.CustomerId) AS 'Percentage'
FROM
(
SELECT COUNT(*) AS 'Count'
FROM dbo.FactTable ft
inner join dbo.Customer c ON ft.CustomerId = c.CustomerId
inner join dbo.Regions r ON ft.RegionId = r.RegionId
WHERE
r.RegionName IN ('A','B','C','D','E') AND
c.HomeRegion IN ('A','B','C','D','E')
) AS 'TMP1', dbo.Customer AS 'TMP2'
使用分析功能
*无需选择或按myHour常数分组
*假设一位客户应一次位于1个区域中(如果不是,则很难选择)
select HomeRegion, CurrentRegion,
count(*) / count(*) over () as overall_share,
count(*) / count(*) over (partition by HomeRegion) as homeregion_share,
from
(SELECT c.HomeRegion, r.RegionName as CurrentRegion, c.CustomerId as CUST
FROM dbo.FactTable ft
inner join dbo.Customer c
ON ft.CustomerId = c.CustomerId
inner join dbo.myTime mt
ON ft.TimeId = mt.ID
inner join dbo.Regions r
ON ft.RegionId = r.RegionId
WHERE mt.myhour = '09'
GROUP BY c.HomeRegion, r.RegionName, c.CustomerId) uni_users
GROUP by HomeRegion, CurrentRegion
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