[英]Sending Data from one page to another without using form php
如何不使用表单将数据从一页发送到另一页? 我正在获取ID并通过GET方法输入
<a href="form.php?id=<?php echo $_GET['id']."&".$_GET['type']; ?>" class="orderbtn">Order Now</a>
当我进入form.php时 ,我填写表单并单击提交按钮,我的表单页面代码如下
form.php
<div id="form">
<p class="rf">*Required Fields </p>
<form action="formsubmitted.php" onsubmit="return formValidate()" method="post" name="myform">
<span class="required" title="Required Field">*</span>
<span style="font-size:16px; color:#000; font-family:Arial, Helvetica, sans-serif;">Name: </span>
<input id="name" title="Enter Your Full Name" type="text" name="name" autofocus="autofocus" required="required" value=""/><br/>
<span class="required" title="Required Field">*</span>
<span style="font-size:16px;color:#000; font-family:Arial, Helvetica, sans-serif;padding-right:10px;">Email:</span>
<input id="email" type="email" name="email" required="required" placeholder="xyz@example.com"/><br/>
<span class="required" title="Required Field">*</span>
<span style="font-size:16px;color:#000; font-family:Arial, Helvetica, sans-serif;">Address:</span>
<input id="address" title="Enter Address" type="text" name="address" required="required" value=""/><br/>
<span class="required" title="Required Field">*</span>
<span style="font-size:16px;color:#000; font-family:Arial, Helvetica, sans-serif;">Contact Number:</span>
<input id="contactno" title="Enter Number" type="text" name="contact" required="required" value=""/><br/>
<input id="submit" name="submit" type="submit" value="Submit"/></span>
</form>
</div>
当我提交时,它进入formsubmitted.php页面,在那里我使用post方法将数据插入数据库
formsubmitted.php
<?php
$connection = mysql_connect("localhost","root","");
$select_db = mysql_select_db("fashion",$connection);
if(!$connection)
{
die ("Could not Connect".mysql_error());
}
$query = "INSERT INTO `order` (flname,email,address,contact) VALUES ('{$_POST['name']}','{$_POST['email']}','{$_POST['address']}','{$_POST['contact']}');";
echo $query . "<br />";
$res = mysql_query($query,$connection);
if(!$res) {die("Could Not Enter Data".mysql_error());}
else { echo "Enter Data Successfully."; }
?>
我想在表单页面的URL中插入要获取的ID和类型,我该怎么做?
您需要添加&type=
<a href="form.php?id=<?php echo $_GET['id']."&type=".$_GET['type']; ?>" class="orderbtn">Order Now</a>
................................................... .................................................................. ^
您需要使用form.php中的$_GET
<?php $id = $_GET['id'];
$type = $_GET['type'];
?>
<form action="formsubmitted.php" onsubmit="return formValidate()" method="post" name="myform">
......
<input name="id" type="hidden" value="<?php echo $id;?>">
<input name="type" type="hidden" value="<?php echo $type;?>">
</form>
在formsubmitted.php中:
<?php echo $_POST['id']; echo $_POST['type']; ?>
您可以在隐藏字段中发送此参数,如下所示:
<input type="hidden" name="type" id="type" value="<?php echo $_GET['type'];?>"/>
而且您需要添加针对XSS的保护
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