在树概念中按属性进行XML多重控制

Question

我想找出一个问题。

我已经对简单的订购问题有所疑问，但我想订购更多详细信息。 检查以下链接： SQL Server：FOR XML按属性排序控制

我举了一个例子。

SQL查询。

select (
    select '123' AS '@id', ( 
        select 
        (
            select 'test' AS '@testid' , '20' AS '@order'
            FOR XML path ('tree') , TYPE
        ),
        (
            select 'test2' AS '@testid' , '30' AS '@order'
            FOR XML path ('tree-order') , TYPE
        ),
        (
            select 'test' AS '@testid' , '10' AS '@order'
            FOR XML path ('tree') , TYPE
        )
        FOR XML path ('Node') , TYPE
    )
    FOR XML path ('Sample') , TYPE
    ),
    (select '456' AS '@id', ( 
        select 
        (
            select 'test' AS '@testid' , '20' AS '@order'
            FOR XML path ('tree') , TYPE
        ),
        (
            select 'test2' AS '@testid' , '30' AS '@order'
            FOR XML path ('tree-order') , TYPE
        ),
        (
            select 'test' AS '@testid' , '10' AS '@order'
            FOR XML path ('tree') , TYPE
        )
        FOR XML path ('Node') , TYPE
    )
    FOR XML path ('Sample') , TYPE)
FOR XML path ('Main') , TYPE

结果：

<Main>
  <Sample id="123">
    <Node>
      <tree testid="test" order="20" />
      <tree-order testid="test2" order="30" />
      <tree testid="test" order="10" />
    </Node>
  </Sample>
  <Sample id="456">
    <Node>
      <tree testid="test" order="20" />
      <tree-order testid="test2" order="30" />
      <tree testid="test" order="10" />
    </Node>
  </Sample>
</Main>

预期结果 ：

<Main>
  <Sample id="123">
    <Node>
      <tree testid="test" order="10" />
      <tree testid="test" order="20" />
      <tree-order testid="test2" order="30" />
    </Node>
  </Sample>
  <Sample id="456">
    <Node>
      <tree testid="test" order="10" />
      <tree testid="test" order="20" />
      <tree-order testid="test2" order="30" />
    </Node>
  </Sample>
</Main>

最后结果 ：

<Main>
  <Sample id="123">
    <Node>
      <tree testid="test" />
      <tree testid="test" />
      <tree-order testid="test2" />
    </Node>
  </Sample>
  <Sample id="456">
    <Node>
      <tree testid="test" />
      <tree testid="test" />
      <tree-order testid="test2" />
    </Node>
  </Sample>
</Main>

这是按树序排列的。

最后我不想在属性中显示订单信息

有人有很棒的主意吗？

谢谢所有对此感兴趣的人。

更新 - - - - - - - - - - - - - - - - - - - -

最后，谢谢大家，我解决了以下有关排序的问题并删除属性问题：

declare @resultData xml = (select @data.query('
  element Main {
    for $s in Main/Sample
    return element Sample {
      $s/@*,
      for $n in $s/Node
      return element Node {
        for $i in $n/* 
        order by $i/@order
        return $i 
      }
    }  
  }'));

  SET @resultData.modify('delete (Main/Sample/Node/tree/@order)');
  SET @resultData.modify('delete (Main/Sample/Node/tree-order/@order)');

  select @resultData

Answer 1

select @data.query('
  element Main {
    for $s in Main/Sample
    return element Sample {
      $s/@*,
      for $n in $s/Node
      return element Node {
        for $i in Node/* 
        order by $i/@order
        return 
          if ($i/self::tree)
          then element tree { $i/@testid }
          else element tree-order { $i/@testid }
        }
      }
    }  
  }')

Answer 2

对我来说有趣的是，在您的原始文章中 ，您指出您是根据SQL查询的结果生成XML的。 如果是我，我将控制该级别的订购。