![](/img/trans.png)
[英]Error running a Maven project for Spring MVC due to 'pom.xml' file?
[英]Minimum pom.xml file for new Maven / Spring MVC project
我对 Maven 和 Spring MVC 完全陌生。 我想要做的是建立一个新的 Spring MVC 项目,使用 Maven(希望这句话有意义),并使用 Eclipse 在 Tomcat 上运行我的 Web 应用程序。
我正在关注此链接上的教程,但pom.xml
文件有问题:
本教程要求创建文件夹结构,并创建一个 pom.xml 文件。 对于初学者,他们要求将此行放在 pom.xml 中:
xml 4.0.0org.springsource.greenbeans.mavenexample11.0-SNAPSHOTOur Simple Project
但是当我这样做时,我的 Eclipse 会抛出一个错误:
[INFO] Scanning for projects...
[ERROR] The build could not read 1 project -> [Help 1]
[ERROR]
[ERROR] The project (D:\projectName\pom.xml) has 1 error
[ERROR] Non-parseable POM D:\projectName\pom.xml: only whitespace content allowed before start tag and not ` (position: START_DOCUMENT seen `... @1:1) @ line 1, column 1 -> [Help 2]
[ERROR]
[ERROR] To see the full stack trace of the errors, re-run Maven with the -e switch.
[ERROR] Re-run Maven using the -X switch to enable full debug logging.
[ERROR]
[ERROR] For more information about the errors and possible solutions, please read the following articles:
[ERROR] [Help 1] http://cwiki.apache.org/confluence/display/MAVEN/ProjectBuildingException
[ERROR] [Help 2] http://cwiki.apache.org/confluence/display/MAVEN/ModelParseException
知道什么是正确的最小 pom.xml 吗? 我尝试了很多东西,但它对我不起作用......
您无需自己创建文件夹结构。 Maven archtype'maven-archetype-webapp'为你做到了。 这是一个很好的教程,可以指导您在eclipse中基本设置MVC项目(以及正确的方法):
使用Maven创建Spring MVC动态Web项目并使其支持Eclipse IDE
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd"> <modelVersion>4.0.0</modelVersion> <groupId>com.beingjavaguys.sample</groupId> <artifactId>SampleSpringMaven</artifactId> <packaging>war</packaging> <version>1.0-SNAPSHOT</version> <name>SampleSpringMaven Maven Webapp</name> <url>http://maven.apache.org</url> <properties> <spring.version>3.0.5.RELEASE</spring.version> <jdk.version>1.6</jdk.version> </properties> <dependencies> <dependency> <groupId>org.springframework</groupId> <artifactId>spring-core</artifactId> <version>${spring.version}</version> </dependency> <dependency> <groupId>org.springframework</groupId> <artifactId>spring-web</artifactId> <version>${spring.version}</version> </dependency> <dependency> <groupId>org.springframework</groupId> <artifactId>spring-webmvc</artifactId> <version>${spring.version}</version> </dependency> <dependency> <groupId>junit</groupId> <artifactId>junit</artifactId> <version>3.8.1</version> <scope>test</scope> </dependency> </dependencies> <build> <finalName>SampleSpringMaven</finalName> <plugins> <plugin> <groupId>org.apache.tomcat.maven</groupId> <artifactId>tomcat7-maven-plugin</artifactId> <version>2.1</version> <configuration> <url>http://localhost:8080/manager/text</url> <server>my-tomcat</server> <path>/SampleSpringMaven</path> </configuration> </plugin> <plugin> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-compiler-plugin</artifactId> <version>3.0</version> <configuration> <source>${jdk.version}</source> <target>${jdk.version}</target> </configuration> </plugin> </plugins> </build>
带有Tomcat的Spring MVC的最小pom.xml
文件可以是:
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.spring.maven</groupId>
<artifactId>minimal-spring</artifactId>
<version>1.0-SNAPSHOT</version>
<packaging>war</packaging>
<dependencies>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-webmvc</artifactId>
<version>4.3.5.RELEASE</version>
</dependency>
</dependencies>
<build>
<plugins>
<plugin>
<groupId>org.apache.tomcat.maven</groupId>
<artifactId>tomcat7-maven-plugin</artifactId>
<version>2.2</version>
<configuration>
<path>/</path>
</configuration>
</plugin>
</plugins>
</build>
</project>
接着:
$ mvn -Dmaven.tomcat.port=8888 tomcat7:run
这是非 spring 启动应用程序的最小 pom.xml,它将生成一个 Spring 5、Java 11 战争文件,您可以将其部署在 tomcat 上。 我在依赖管理中使用 spring bom 来锁定 spring 框架 jars 的版本
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.yourco</groupId>
<artifactId>spring-mvc-demo</artifactId>
<packaging>war</packaging>
<version>0.0.1-SNAPSHOT</version>
<name>spring-security Maven Webapp</name>
<url>http://maven.apache.org</url>
<properties>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
<project.reporting.outputEncoding>UTF-8</project.reporting.outputEncoding>
<java.version>11</java.version>
</properties>
<dependencyManagement>
<dependencies>
<!-- https://mvnrepository.com/artifact/org.springframework/spring-framework-bom -->
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-framework-bom</artifactId>
<version>5.3.9</version>
<type>pom</type>
<scope>import</scope>
</dependency>
</dependencies>
</dependencyManagement>
<dependencies>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-webmvc</artifactId>
</dependency>
<dependency>
<groupId>junit</groupId>
<artifactId>junit</artifactId>
<version>3.8.1</version>
<scope>test</scope>
</dependency>
<dependency>
<groupId>javax.servlet</groupId>
<artifactId>javax.servlet-api</artifactId>
<version>4.0.1</version>
<scope>provided</scope>
</dependency>
</dependencies>
<build>
<finalName>spring-mvc-demo</finalName>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-compiler-plugin</artifactId>
<version>3.8.1</version>
<configuration>
<source>${java-version}</source>
<target>${java-version}</target>
</configuration>
</plugin>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-war-plugin</artifactId>
<version>3.3.2</version>
</plugin>
</build>
</project>
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.