[英]Insert a new row for every change in value in a column
我有一个sql表,其中对于某列(例如Column C)中的值的每个更改,我想在其下插入新行以创建新事务。 我不确定如何找到该值更改并插入新行。 我一直通过导入到表中的csv文件中的VB代码执行此操作,但是无法用SQL编写它。
Sub InsertRows()
Dim r As Long, mcol As String, i As Long
' find last used cell in Column A
r = Cells(Rows.Count, "A").End(xlUp).Row
' get value of last used cell in column A
mcol = Cells(r, 1).Value
' insert rows by looping from bottom
For i = r To 2 Step -1
If Cells(i, 1).Value <> mcol Then
mcol = Cells(i, 1).Value
Rows(i + 1).Insert
End If
Next i
End Sub
这是示例数据
ID JOB FNAME LNAME ADDRESS1 ADDRESS2 DATE Concatenated
1234 A John Smith 4378 Anna St Seattle-WA-98040 12/24/2013 1234-A-41632
1234 A John Doe 3564 Lucie Ave Mercer Island-WA-98040 12/24/2013 1234-A-41632
1235 A Alex Smith 4554 Devon Ave Chicago-IL-60563 12/24/2013 1235-A-41632
1235 A Eli Manning 5555 Stranz Lane Dallas-TX-75213 12/24/2013 1235-A-41632
1233 B John Smith 4378 Anna St Seattle-WA-98040 12/24/2013 1233-B-41632
1233 C John Doe 3564 Lucie Ave Mercer Island-WA-98040 12/24/2013 1233-C-41632
1236 D Alex Smith 4554 Devon Ave Chicago-IL-60563 12/24/2013 1236-D-41632
1236 E Eli Manning 5555 Stranz Lane Dallas-TX-75213 12/24/2013 1236-E-41632
以下是所需的输出
ID JOB FNAME LNAME ADDRESS1 ADDRESS2 DATE Concatenated
1234 A John Smith 4378 Anna St Seattle-WA-98040 12/24/2013 1234-A-41632
1234 A John Doe 3564 Lucie Ave Mercer Island-WA-98040 12/24/2013 1234-A-41632
1235 A Alex Smith 4554 Devon Ave Chicago-IL-60563 12/24/2013 1235-A-41632
1235 A Eli Manning 5555 Stranz Lane Dallas-TX-75213 12/24/2013 1235-A-41632
1233 B John Smith 4378 Anna St Seattle-WA-98040 12/24/2013 1233-B-41632
1237 C John Doe 3564 Lucie Ave Mercer Island-WA-98040 12/24/2013 1237-C-41632
1236 D Alex Smith 4554 Devon Ave Chicago-IL-60563 12/24/2013 1236-D-41632
1236 E Eli Manning 5555 Stranz Lane Dallas-TX-75213 12/24/2013 1236-E-41632
我尝试在其中找到更改并在每次更改后插入一行的“已连接”列。 任何帮助,将不胜感激。
您确实想编写一个从数据源运行到数据库或时间取决于数据库的存储过程。
这是代码
开始;
ALTER TABLE Test_table添加列b1(10,2);
更新test_table SET romney_pct = CAST(romney AS DECIMAL(10,2))/ CAST(uspres_total AS DECIMAL(10,2);
承诺;
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