[英]Mysql select count per category per day
我有三张桌子。
categories
表
id | 名称
items
表
id | 名称| category_id
orders
表
id | item_id | date_time | 交易代码
现在如何在查询中每天为每个类别选择具有特定交易代码的总订单。
所需结果:
Date Category Total
2013-12-01 001 6
2013-12-01 002 0
2013-12-01 003 1
2013-12-02 001 14
2013-12-02 002 2
2013-12-02 003 0
2013-12-03 001 11
2013-12-03 002 4
2013-12-03 003 4
什么是编写此查询的最有效方法。
这是我到目前为止尝试过的:
SELECT DATE(od.trans_date) AS Date, ct.number AS Category, COUNT(od.id) AS Total
from orders od
JOIN items im ON od.item_id = im.id
JOIN categories ct ON im.category_id = ct.id
WHERE od.trans_date BETWEEN '2013-12-01 00:00:00' AND '2013-12-03 23:59:59'
AND (od.transaction_code = 17 OR od.transaction_code = 15)
GROUP BY DATE(od.trans_date), ct.number ASC;
谢谢
我建议将您的JOINS
更改为LEFT JOINS
以便您的结果将包括没有任何项目的订单...
SELECT DATE(od.trans_date) AS Date, ct.number AS Category, COUNT(od.id) AS Total
from orders od
LEFT JOIN items im ON od.item_id = im.id
LEFT JOIN categories ct ON im.category_id = ct.id
WHERE od.trans_date BETWEEN '2013-12-01 00:00:00' AND '2013-12-03 23:59:59'
AND (od.transaction_code = 17 OR tr.transaction_code = 15)
GROUP BY DATE(od.trans_date), ct.number ASC;
另外,您可能需要切换JOINS
的顺序,以便显示所有类别,而不是所有顺序。
SELECT DATE(od.trans_date) AS Date, ct.number AS Category, COUNT(od.id) AS Total
FROM categories ct
LEFT JOIN items im ON ct.id = im.category_id
LEFT JOIN orders od ON im.id = od.item_id
WHERE od.trans_date BETWEEN '2013-12-01 00:00:00' AND '2013-12-03 23:59:59'
AND (od.transaction_code = 17 OR tr.transaction_code = 15)
GROUP BY DATE(od.trans_date), ct.number ASC;
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