[英]How would I Find a Word, and Take all characters after the first occurrence of the word, but stop after an occurrence of a different word?
例如
NSString *string = @"I need help finding a string";
NSString *newString = @"need";
我不仅需要为这个字符串工作,还需要它。 一个示例是采用字符串并删除单词“ I”之后和单词“ help”之前的所有内容。 非常感谢你!
为了清晰起见,从评论移至:
NSString *string = @"I need help finding a string";
NSRange rr2 = [TWEET rangeOfString:@"I "];
NSRange rr3 = [TWEET rangeOfString:@" help"];
int lengt = rr3.location - rr2.location;
int location = rr2.location + rr2.length;
NSRange aa;
aa.location = location;
aa.length = lengt;
NSString *link;
link = [TWEET substringWithRange:aa];
NSLog(@"The link is %@", link);
一种方法是将字符串拆分为单个单词,然后遍历整个单词,首先搜索第一个单词,然后将每个单词添加到新字符串中,直到找到它,然后搜索第二个单词,然后才发现添加剩下的话。
在代码中看起来可能像这样:
NSString *myString = @"I need help finding a string";
NSString *firstWord = @"need";
NSString *secondWord = @"a";
NSMutableString *newString = [NSMutableString stringWithString:@""];
int index = 0;
for (NSString *word in [myString componentsSeparatedByString:@" "]) {
if(index == 0) {
if([word isEqualToString:firstWord])
index = 1;
[newString appendFormat:@"%@ ", word];
}
else if(index == 1) {
if([word isEqualToString:secondWord])
index = 2;
}
else
[newString appendFormat:@"%@ ", word];
}
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