[英]What's wrong with this C library function usage?
我正在尝试比较两个char数组。 但是,DoSomething()函数永远不会被调用。 我不知道为什么。
我究竟做错了什么?
//The value the user types in will be stored here:
char TempStorage[]={0,0,0,0,0,0};
//User types in a sequence here:
GetInput();
//One of the sequences that TempStorage will be compared to.
char Sequence[]={1,2,3,4,0,0};
//If the user typed in "123400" then DoSomething().
if(memcmp(TempStorage, Sequence, sizeof(TempStorage) == 0))
{
DoSomething();
}
放置错误的括号。
if(memcmp(TempStorage, Sequence, sizeof(TempStorage) == 0))
应该
if(memcmp(TempStorage, Sequence, sizeof(TempStorage)) == 0)
您解析并放置在数组中的那六个输入是真的吗? 还是TempStorage
是输入的ASCII字符字符串? 如果是后者,则应该使用字符串比较,并且应该对要比较的字符使用正确的ASCII码。 (这是0x30
或'1'' for
1” .) A string comparison stops as soon as one of the strings is a NUL (
'\\ 0'`), .) A string comparison stops as soon as one of the strings is a NUL (
,这意味着您不会比较无意义的填充(如果存在)。
char *input = GetInput();
if (strcmp(input, "1234") == 0) { ... }
您的字符将解析为ASCII值,因此您应将其指定为:
char Sequence[]={'1','2','3','4',0,0};
或与实际字符串进行比较,例如:
char Sequence[]="1234";
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