Java For循环和char数组

Question

我正在制作“代码解码器”-因此，共有3行，第一行是参考字符串，第二行是混杂的，然后第三行是根据第一和第二个字符串的匹配来计算的。 例：

1. 敏捷的棕色狐狸跳过了懒狗

2. UIFARVJDLACSPXOAGPYAKVNQTAPWFSAUIFAMB ZAEPH

3. XFABSFAWFSZACBEAQFPQMFAEPJOHAWFSZACBEAUIJOHTAIBAIB

我正在做的是获取3个字符串，将它们转换为char数组，然后浏览第一个字符串，找到它在字母数组中的位置，然后在该位置输入另一个数组中第二个字符串的字母在同一个地方。 因此，稍后，我可以在字母表中找到一个字母，并在第二个数组中获取其对应的字母。

问题-没有任何内容输入到第二个数组中...空了。

让我知道是否需要澄清。

    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    System.out.print("Enter First String:"); // First String
    String first_string = br.readLine();
    System.out.print("Enter Second String:"); // Second String 
    String second_string = br.readLine();
    System.out.print("Enter Third String:"); // Third String 
    String third_string = br.readLine();

    char[] first = first_string.toCharArray();
    char[] second = second_string.toCharArray();
    char[] third = third_string.toCharArray();
    char[] compare_a = {'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'}; //length = 26
    char[] compare_b = new char[26]; //length = 26

    for(int x =0; x < first.length ; x++){// going through first array
        char first_letter = first[x]; // gets letter from first string

        for(int z = 0; z < 26; z++){ // looks through alphabet for the position of the letter
            if(first_letter == compare_a[z]){ // if the letter is found at a certain position
                // System.out.println(first_letter + " = " + compare_a[z] + " " + compare_b[z]  + " " +  second[x]);
                compare_b[z] = second[x]; // insert into the same position on the second array
            }
        }
    }

    for(int t =0; t<26; t++){

        char m = compare_b[t];
        System.out.print(m); //Printing out array of new letters
    }
}

注意：

当我尝试将结果输出到字符串时，它正确显示-

   letters = letters + second[x];

它只是不进入数组...

Answer 1

窃听器

应该

compare_b[z] = second[z]; 

但是

compare_b[z] = second[x];

固定码

public static void main(String[] args) {

        String first_string = "THE QUICK BROWN FOX JUMPS OVER THE LAZY DOG";
        String second_string = "UIFARVJDLACSPXOAGPYAKVNQTAPWFSAUIFAMB ZAEPH";
        String third_string = "XFABSFAWFSZACBEAQFPQMFAEPJOHAWFSZACBEAUIJOHTAIBAIB";

        char[] first = first_string.toCharArray();
        char[] second = second_string.toCharArray();
        char[] third = third_string.toCharArray();
        char[] compare_a = {'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'}; //length = 26
        char[] compare_b = new char[26]; //length = 26

        for (int x = 0; x < first.length; x++) {// going through first array
            char first_letter = first[x]; // gets letter from first string

            for (int z = 0; z < 26; z++) { // looks through alphabet for the position of the letter
                if (first_letter == compare_a[z]) { // if the letter is found at a certain position
                    // System.out.println(first_letter + " = " + compare_a[z] + " " + compare_b[z]  + " " +  second[x]);
                    compare_b[z] = second[z]; // insert into the same position on the second array
                }
            }
        }

        for (int t = 0; t < 26; t++) {

            char m = compare_b[t];
            System.out.print(m); //Printing out array of new letters
        }
    }

固定结果是

UIFARVJDLACSPXOAGPYAKVNQTA