[英]php update mysql table via form, reload information on page immediately
我正在创建一个页面,其中房间预订显示在表格中,并且可以更新或删除它们。
保留来自MySQL数据库的表保留。
它可以工作,但是我希望在按下按钮后立即在页面上更新数据库中的信息。
例如,如果现在我将用户名从“ person”设置为“ another person”,则该字段将在数据库中正确更新,但是我需要刷新页面以查看表中的更新。
我怎样才能做到这一点?
<table border="1">
<tr><td>Datum</td><td>Start</td><td>Stop</td><td>Gebruikersnaam</td></tr>
<?php
$now = date("Y-m-d");
$query = "SELECT * FROM reservations WHERE (roomid = " . 45 . " AND end > NOW() ) ORDER BY start";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)){
$reservationid=$row["reservationid"];
$username=$row["username"];
$aantal=$row["numberingroup"];
$reservationid=$row["reservationid"];
$start=$row["start"];
$end=$row["end"];
$roomid=$row["roomid"];
?>
<form action="" method="post">
<tr><td><input name="StartDate" value="<? echo $StartDate; ?>" /></td><td><input name="StartTime" value="<? echo $StartTime; ?>" /></td><td><input name="StopTime" value="<? echo $StopTime; ?>" /></td><td><input name="username" value="<? echo $username;?>" /></td><td><input type="submit" value="update" name="<?php echo 'update_' . $reservationid; ?>" /></td><td><input type="submit" value="delete" name="<?php echo 'delete_' . $reservationid; ?>" /></td><td><? echo $reservationid; ?></td></tr></form>
<?php
//DELETE
if(isset($_POST['delete_' . $reservationid]))
{
$deletequery = "DELETE FROM reservations WHERE reservationid=" . $reservationid;
if(mysql_query($deletequery)){
echo "<p><b>Boeking verwijderd</b></p>";}
else {
echo "<p><b>Boeking niet verwijderd</b></p>";}
}
//UPDATE
if(isset($_POST['update_' . $reservationid]))
{
$NewStartDate = explode("-",$_POST[StartDate]);
$newstartdate = $NewStartDate[2] . "-" . $NewStartDate[1] . "-" . $NewStartDate[0];
$newstarttime = $_POST[StartTime] . ":00";
$newenddate = $newstartdate;
$NewEndTime = explode(":",$_POST[StopTime]);
$newendtime = mktime($NewEndTime[0],($NewEndTime[1]-1),59);
$newendtime = date("H:i:s",$newendtime);
$UpdateStart = $newstartdate . " " . $newstarttime;
$UpdateEnd = $newenddate . " " . $newendtime;
$UpdateUsername = $_POST[username];
$updatequery = "UPDATE reservations SET start='$UpdateStart', end='$UpdateEnd', username='$UpdateUsername' WHERE reservationid=" . $reservationid;
if(mysql_query($updatequery)){
echo "<p><b>Updated " . $reservationid . " " . $UpdateStart . " " . $UpdateEnd . " " . $UpdateUsername . "</b></p>";}
else {
echo "<p><b>FAILURE IS NOT AN OPTION. AGAIN!</b></p>";}
}
?>
<?php
}
mysql_close();
?>
工作代码为:
<?php
//DELETE
if(isset($_POST['delete_' . $_POST[updateid]]))
{
$deletequery = "DELETE FROM reservations WHERE reservationid=" . $_POST[updateid];
if(mysql_query($deletequery)){
echo "<p><b>Boeking verwijderd</b></p>";
}
else {
echo "<p><b>FAILURE IS NOT AN OPTION. AGAIN!</b></p>";
}
}
//UPDATE
if(isset($_POST['update_' . $_POST[updateid]]))
{
$UpdateID = $_POST[updateid];
$NewStartDate = explode("-",$_POST[StartDate]);
$newstartdate = $NewStartDate[2] . "-" . $NewStartDate[1] . "-" . $NewStartDate[0];
$newstarttime = $_POST[StartTime] . ":00";
$newenddate = $newstartdate;
$NewEndTime = explode(":",$_POST[StopTime]);
$newendtime = mktime($NewEndTime[0],($NewEndTime[1]-1),59);
$newendtime = date("H:i:s",$newendtime);
$UpdateStart = $newstartdate . " " . $newstarttime;
$UpdateEnd = $newenddate . " " . $newendtime;
$UpdateUsername = $_POST[username];
$updatequery = "UPDATE reservations SET start='$UpdateStart', end='$UpdateEnd', username='$UpdateUsername' WHERE reservationid='$UpdateID'";
if(mysql_query($updatequery)){
echo "<p><b>Updated " . $reservationid . " " . $UpdateStart . " " . $UpdateEnd . " " . $UpdateUsername . "</b></p>";
}
else {
echo "<p><b>FAILURE IS NOT AN OPTION. AGAIN!</b></p>";
}
// echo "<p><b>Updated " . $reservationid . " " . $UpdateStart . " " . $UpdateEnd . " " . $UpdateUsername . "</b></p>";
}
?>
<?php
$query = "SELECT * FROM reservations WHERE (roomid = " . 45 . " AND end > NOW() ) ORDER BY start";
$result = mysql_query($query) or die(mysql_error());
?>
<table border="1">
<tr><td>Datum</td><td>Start</td><td>Stop</td><td>Gebruikersnaam</td></tr>
<?php
while($row = mysql_fetch_array($result)){
$reservationid=$row["reservationid"];
$username=$row["username"];
$aantal=$row["numberingroup"];
$reservationid=$row["reservationid"];
$start=$row["start"];
$end=$row["end"];
$roomid=$row["roomid"];
$startdate = explode(" ",$start);
$startdate[0] = explode("-",$startdate[0]);
$startdate[1] = explode(":",$startdate[1]);
$StartFormat = mktime($startdate[1][0],$startdate[1][1],$startdate[1][2],$startdate[0][1],$startdate[0][2],$startdate[0][0]);
$StartDate = date("d-m-Y",$StartFormat);
$StartTime = date("H:i",$StartFormat);
$stopdate = explode(" ",$end);
$stopdate[0] = explode("-",$stopdate[0]);
$stopdate[1] = explode(":",$stopdate[1]);
$StopFormat = mktime($stopdate[1][0],$stopdate[1][1],($stopdate[1][2]+1),$stopdate[0][1],$stopdate[0][2],$stopdate[0][0]);
$StopDate = date("d-m-Y",$StopFormat);
$StopTime = date("H:i",$StopFormat);
?>
<form action="" method="post">
<tr><td><input type="hidden" name="updateid" value="<?php echo $reservationid; ?>" /> <input name="StartDate" value="<? echo $StartDate; ?>" /></td><td><input name="StartTime" value="<? echo $StartTime; ?>" /></td><td><input name="StopTime" value="<? echo $StopTime; ?>" /></td><td><input name="username" value="<? echo $username;?>" /></td><td><input type="submit" value="update" name="<?php echo 'update_' . $reservationid; ?>" /></td><td> <input type="submit" value="delete" name="<?php echo 'delete_' . $reservationid; ?>" /></td> </tr>
</form>
<?php
}
mysql_close();
?>
</table>
将进行更新和删除的逻辑移到进行渲染的逻辑上方:
<?php
// DELETE (your delete stuff)
// UPDATE (your update stuff)
// RETRIEVE (your SELECT query)
?>
<table> <!-- your table markup -->
<?php
// RENDER (your while loop and such)
您还需要稍微调整一下逻辑。 您正在使用SELECT
的$reservationid
进行删除和更新。 这是行不通的,因为每次页面加载都会刷新PHP的执行上下文。 您需要以每种形式(可能在隐藏字段中)存储预订ID,然后从$_POST
检索该ID。
顺便说一句,您的代码很容易受到SQL注入的攻击。 另外,您应该看看使用mysqli
或PDO
; 当前版本的PHP中不推荐使用mysql_connect
。
您可以为此使用jQuery。 您必须进行$.ajax
( http://api.jquery.com/jquery.ajax/ )调用。 在回调中,您可以填充/设置所需的字段。 $('#idofelement').html()
您需要$('#idofelement').html()
( http://api.jquery.com/html/ )。 如果您有任何疑问,请不要害怕提出;)祝您好运!
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