Symfony私人Beta版登录

Question

我希望在即将推出的symfony网站上设置私人Beta。 我在服务器上的文本文件中提供了一个受邀人员的电子邮件地址列表，以供检查。我想在他们尝试未经许可访问该网站时向他们提供html表单。 输入人员的电子邮件地址后，应将其重定向到主页。 棘手的部分是，过去我使用FOSUserBundle并已使用整个帐户登录系统。 我应该如何解决这个问题？ 使用电子邮件登录的人还没有帐户，因此我不能仅在其用户文档中添加INVITED_USER之类的角色，因此我正在考虑尝试在其会话中存储其状态，并使用symfony 2.4的allow_if表达式，但出现错误：

致命错误：C：\\ wamp \\ www \\ vendor \\ symfony \\ symfony \\ src中未捕获的异常'Symfony \\ Component \\ Config \\ Definition \\ Exception \\ InvalidConfigurationException'，消息为“ security.access_control.17”下的“无法识别的选项” allow_if” 306行上的\\ Symfony \\ Component \\ Config \\ Definition \\ ArrayNode.php

我的security.yml文件如下所示：

security:
    encoders:
        FOS\UserBundle\Model\UserInterface: sha512

    role_hierarchy:
        ROLE_ADMIN:       ROLE_USER
        ROLE_SUPER_ADMIN: ROLE_ADMIN

    providers:
        fos_userbundle:
            id: fos_user.user_provider.username_email

    firewalls:
        beta:
            pattern: ^/
            anonymous: ~
            form_login:
                login_path: /beta
                check_path: /beta_invite_check
                always_use_default_target_path: true
                default_target_path: /
            logout:
                path: /logout
                target: /
        main:
            pattern:  ^/
            form_login:
                check_path: /login_check
                provider: fos_userbundle
                always_use_default_target_path: false
                default_target_path: /profile
                use_referer: true
                success_handler: security.authentication.handler

            logout:
                path:   /logout
                target: /
                invalidate_session: false
            anonymous: ~

        login:
            pattern: ^/login$
            security: false

    access_control:
        - { path: ^/beta, role: IS_AUTHENTICATED_ANONYMOUSLY }
        - { path: ^/login$, role: IS_AUTHENTICATED_ANONYMOUSLY }
        - { path: ^/register, role: IS_AUTHENTICATED_ANONYMOUSLY }
        - { path: ^/resetting, role: IS_AUTHENTICATED_ANONYMOUSLY }
        - { path: ^/account, roles: ROLE_USER}
        - { path: /_wdt/.*, role: IS_AUTHENTICATED_ANONYMOUSLY }
        - { path: /_profiler/.*, role: IS_AUTHENTICATED_ANONYMOUSLY }
        - { path: ^/profile, role: ROLE_USER }
        - { path: ^/submit, role: ROLE_USER }
        - { path: ^/submissions, role: ROLE_USER }
        - { path: ^/uploadCredits, role: ROLE_USER }
        - { path: ^/transactions, role: ROLE_USER }
        - { path: ^/activity, role: ROLE_USER }
        - { path: ^/browse/join, role: ROLE_USER }
        - { path: ^/browse/follow, role: ROLE_USER }
        - { path: ^/browse/unfollow, role: ROLE_USER }
        - { path: ^/player/rating, role: ROLE_USER }
        - { path: ^/, allow_if: "'BETA_ALLOWED' == request.getSession().beta" }

有人知道为什么会这样吗？ allow_if似乎是一个新功能，所以也许某人的捆绑软件在其中表现不佳？ 这也是我的composer.json文件，以防万一：

{
    "name": "symfony/framework-standard-edition",
    "description": "The \"Symfony Standard Edition\" distribution",
    "autoload": {
        "psr-0": { "": "src/" }
    },
    "require": {
        "doctrine/mongodb-odm": "1.0.*@dev",
        "doctrine/mongodb-odm-bundle": "3.0.*@dev",
        "php": ">=5.3.3",
        "symfony/symfony": "2.4.1",
        "doctrine/orm": "~2.2,>=2.2.3",
        "doctrine/doctrine-bundle": "1.2.*",
        "twig/extensions": "1.0.*",
        "symfony/assetic-bundle": "2.1.*",
        "hipaway-travel/mandrill-bundle": "dev-master",
        "symfony/monolog-bundle": "2.2.*",
        "sensio/distribution-bundle": "2.2.*",
        "sensio/framework-extra-bundle": "2.2.*",
        "sensio/generator-bundle": "2.2.*",
        "jms/security-extra-bundle": "dev-master",
        "friendsofsymfony/user-bundle": "~2.0.*@dev",
        "jms/di-extra-bundle": "dev-master",
        "sonata-project/media-bundle": "2.2.*@dev",
        "sonata-project/admin-bundle": "2.2.*@dev",
        "sonata-project/core-bundle": "2.2.*@dev",
        "sonata-project/doctrine-mongodb-admin-bundle": "2.2.*@dev",
        "avalanche123/imagine-bundle": "v2.1",
        "braintree/braintree_php" : "dev-master",
        "cometcult/braintree-bundle": "dev-master",
        "paypal/rest-api-sdk-php": "dev-master",
        "kmj/paypalbridgebundle": "dev-master",
        "hwi/oauth-bundle": "0.3.*@dev",
        "cboden/Ratchet": "0.3.0",
        "react/zmq": "0.2.*"

    },
    "scripts": {
        "post-install-cmd": [
            "Sensio\\Bundle\\DistributionBundle\\Composer\\ScriptHandler::buildBootstrap",
            "Sensio\\Bundle\\DistributionBundle\\Composer\\ScriptHandler::clearCache",
            "Sensio\\Bundle\\DistributionBundle\\Composer\\ScriptHandler::installAssets",
            "Sensio\\Bundle\\DistributionBundle\\Composer\\ScriptHandler::installRequirementsFile"
        ],
        "post-update-cmd": [
            "Sensio\\Bundle\\DistributionBundle\\Composer\\ScriptHandler::buildBootstrap",
            "Sensio\\Bundle\\DistributionBundle\\Composer\\ScriptHandler::clearCache",
            "Sensio\\Bundle\\DistributionBundle\\Composer\\ScriptHandler::installAssets",
            "Sensio\\Bundle\\DistributionBundle\\Composer\\ScriptHandler::installRequirementsFile"
        ]
    },
    "config": {
        "bin-dir": "bin"
    },
    "minimum-stability": "dev",
    "extra": {
        "symfony-app-dir": "app",
        "symfony-web-dir": "web"
    }
}

提前致谢！

Answer 1

我之前实现此方法的方式是使用邀请实体。

1. 生成邀请码，并通过电子邮件向用户发送注册表格的链接
2. 仅接受包含有效邀请码的注册

您需要使用新的邀请字段和注册控制器操作 扩展注册表单 。

基本上阅读以下内容： https : //github.com/FriendsOfSymfony/FOSUserBundle/blob/master/Resources/doc/adding_invitation_registration.md

:)

TLDR; 不用担心首次登录，而使用邀请系统。