程序不能作为Java Applet运行

Question

我编写了一个无法作为Java Applet运行的简单程序。 当我尝试运行程序时，会弹出一个框架并询问要运行哪个程序。 我点击了我写的程序，如下所示。 令人惊讶的是，Eclipse会在同一个默认包中运行其他程序。 谁能告诉我出了什么问题？

这是Java的艺术与科学第6章练习3中的一个程序：

ApproxPIValue

import acm.util.*;

public class ApproxPIValue {

public void run() {
    int total = 0; //This variable counts the amount of time x^2 + y^2 < 1.//
    for (int a = 0; a < 10000; a++) { 
        double x = rgen.nextDouble(-1.0, 1.0);
        double y = rgen.nextDouble(-1.0, 1.0);
        if (Math.sqrt(x) + Math.sqrt(y) < 1) { //x^2 + y^2 < 1 means that     this pair number will fall into the circle with radius of 1 centered in the middle     of the coordinates.  
            total++;
        }
        double approxPIValue = total / 10000 * 4; //total / 100000 is the approximate ratio of the area of the circle over the area of the square. The approximate ratio would be close to PI/4 if x and y are randomly chosen. So total / 10000 * 4 will give the approximate PI.//
        System.out.print(approxPIValue);
    }
}

/* set RandomGenerator as an instance variable. */
private RandomGenerator rgen = new RandomGenerator();
}

我还想提出另一个无效的程序。

CoinFace

import acm.util.*;

/**
 * This class decides the face of a coin. 
 * 1 and 2 represent correspondingly Heads and Tails.
 * Clients can get the "face" of the coin by calling getState() method.
 */

public class CoinFace {

public CoinFace() {
    state = rgen.nextInt(1, 2);
}


/* private instance variable.  */
private int state;

public int getState() {
    return state;
}

/* declare RandomGenerator as an instance variable. */
private RandomGenerator rgen = new RandomGenerator();
}

ConsecutiveHeads

public class ConsecutiveHeads extends CoinFace{
public void run () {
    while (true) {
        int totalFlip = 0;
        int consecutiveHeads = 0; //the time of getting consecutive Heads when flipping a coin.//
        CoinFace a = new CoinFace();
        if (a.getState() == 1) {
            System.out.print("Heads");
            totalFlip++;
            consecutiveHeads++;
        } else if (consecutiveHeads == 3) {
            System.out.print("It took " + totalFlip + " to get 3 consecutive heads." );
            break;
        } else {
            System.out.print("Tails");
            consecutiveHeads = 0;
            totalFlip++;
        }
    }
}
}

由于我无法运行该程序，我不知道程序将如何运行。 在此先感谢任何有关改进计划的解决方案和建议！

Answer 1

ACM JApplet显然被称为Program 。 一个应用程序 必须扩展Program如果它要嵌入到网页中。

但为什么要编写applet？ 如果是由于规格。 请教老师， 为什么CS老师应该停止教Java小程序 。