Java中的石头，纸，剪刀简单游戏

Question

嗨，我正在做一个简单的石头，纸，剪刀游戏，在获取比较方法执行时遇到了一些麻烦。 游戏提示用户进行输入，然后使用computersTurn方法允许计算机随机选择石头纸或剪刀。 当我尝试将这两个值都传递给我的compare方法时，它似乎不起作用。 任何建议都很棒！

import java.util.Scanner;



public class sillyGame {

public static void compare (String choice1, String choice2)

{

    if (choice1.equals(choice2))

    {

    System.out.println("The result is a tie!");   

    }



    if (choice1.contains("rock"))

    {
        if (choice2.contains("scissors"))
        {
            System.out.println("rock wins");
        }

        if (choice2.contains("paper"))
        {
            System.out.println("paper wins");
        }
    }   



        if (choice1.contains("scissors"))
    {
        if (choice2.contains("rock"))
        {
            System.out.println("rock wins");
        }

        if (choice2.contains("paper"))
        {
            System.out.println("scissors wins");
        }

    }



    if (choice1.contains("paper"))

    {
        if (choice2.contains("rock"))
        {
            System.out.println("paper wins");
        }

        if (choice2.contains("scissors"))
        {
            System.out.println("scissors wins");
        }

    }




}

public static String computersTurn(String compFinalChoice, double randomNum){

randomNum = Math.random();


    if (randomNum < 0.34) 
    {
        compFinalChoice = "rock";

    } 

    else if(randomNum <= 0.67) 
    {
        compFinalChoice = "paper";

    } 

    else 
    {
        compFinalChoice = "scissors";

    }

       System.out.println("The computer chooses " + compFinalChoice);
      return compFinalChoice;
}



public static void main(String[] args) {

    Scanner scan = new Scanner(System.in);
    System.out.println("Do you choose rock, paper or scissors?");
    String userChoice = scan.nextLine();
    String computerDec = " ";
    double rand = 0.0;
    computersTurn(computerDec, rand);
    compare(userChoice, computerDec); 
}

Answer 1

您不能从调用方更新字符串（或双精度字符串），所以我认为您应该重构computersTurn

public static String computersTurn() {
  String choice = "scissors";
  double randomNum = Math.random();
  if (randomNum < 0.34) {
    choice = "rock";
  } else if (randomNum <= 0.67) {
    choice = "paper";
  }
  System.out.println("The computer chooses "
      + choice);
  return choice;
}

然后您可以在main执行类似的操作

String computerDec = computersTurn();

要么

String userChoice = scan.nextLine();
compare(userChoice, computersTurn());

Answer 2

您的computersTurn方法不需要任何参数。 您只需传递" "和0.0 。

尝试将其更改为以下方法：

public static String computersTurn() {

    // declare them here
    double randomNum = Math.random();
    String compFinalChoice = "";

    if (randomNum < 0.34) {
        compFinalChoice = "rock";
    }
    else if(randomNum <= 0.67) {
        compFinalChoice = "paper";
    } 
    else {
        compFinalChoice = "scissors";
    }

    System.out.println("The computer chooses " + compFinalChoice);
    return compFinalChoice;
}

然后在您的main方法中，确保在调用computersTurn()方法时将其分配给String。 调用它对您没有任何帮助； 您需要保留返回值：

public static void main(String args[]) 
{
    Scanner scan = new Scanner(System.in);
    System.out.println("Do you choose rock, paper or scissors?");
    String userChoice = scan.nextLine();
    String computerDec = computersTurn(); // assign it here
    compare(userChoice, computerDec);
}