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错误提示:“语句无法解析重载函数的地址”

[英]Error saying, “statement cannot resolve address of overloaded function”

我是一个初学者程序员,所以看起来有些混乱,但是我一直遇到标题中提到的问题。 无论在哪里我试图把endl ; 它一直给我同样的错误。 另外,当我运行代码时,我第二家商店的总数显示正确,而第一家商店的总数却不正确。 关于如何解决此问题的任何想法? 我在Windows 7计算机上使用代码块。

#include <iostream> //Allows cout/cin
#include <ctime> //Allows time
#include <iomanip> //Allows setprecision

using namespace std;

int main()
{
    //Include header

    //Input variables
    double widgetStores;
    double numberSoldFirst1;
    double numberSoldFirst2;
    double numberSoldSecond1;
    double numberSoldSecond2;
    double widgetsLeftS1W2;
    double widgetsLeftS2W1;
    double widgetsLeftS2W2;

    //Start Clock
    clock_t begin, end;
    double time_spent;
    begin = clock();

    //Prompt for total number in stores

    cout << "Total number of widgets at each store starting with :";
    cin >> widgetStores;

    double widgetStore1=widgetStores;
    double widgetStore2=widgetStores;
    double widgetsLeftS1W1;


    //Prompt for amount sold during first and second week

    cout << "How many widgets were sold at Store 1 the first week? ";
    cin >> numberSoldFirst1;
    cout << "How many widgets were sold at Store 1 the 2nd week? ";
    cin >> numberSoldSecond1;
    cout << "How many widgets were sold at Store 2 the first week? ";
    cin >> numberSoldFirst2;
    cout << "How many widgets were sold at Store 2 the 2nd week? ";
    cin >> numberSoldSecond2;

    //Calculate Number of widgets
    widgetsLeftS1W1-=(widgetStore1-numberSoldFirst1);
    widgetsLeftS1W2-=(numberSoldFirst1-numberSoldSecond1);
    widgetsLeftS2W1-=(widgetStore2-numberSoldFirst2);
    widgetsLeftS2W2-=(numberSoldFirst2-numberSoldSecond2);

    //Display Values
    cout << "Store 1 has " << widgetsLeftS1W2 << " widgets left after the 2nd week.";
    cout << "Store 2 has " <<widgetsLeftS2W2 << " widgets left after the 2nd week.";

    //Show time elapsed
    end = clock();
    time_spent = (double)(end - begin) / CLOCKS_PER_SEC;
    cout << setprecision(2) << fixed << "****Elapsed time:" <<time_spent/60 <<        "minutes****";
    return 0;

你尝试过类似的东西吗

cout << "Total number of widgets at each store starting with :";
cin >> widgetStores;
cout << endl; //Added this

cin没有<<操作符,因此您需要将其发送给cout。

编辑:我发现了您遇到的错误。 我想您正在尝试按字面意思排成一行

ENDL;

而且那无处不在...

该程序唯一的编译错误是,在初始化它们之前,您使用的是widgetsLeftS1W1widgetsLeftS1W2widgetsLeftS2W1widgetsLeftS2W2

在此处输入图片说明

您可能需要=而不是-=

当你说

widgetsLeftS1W1 -= (widgetStore1-numberSoldFirst1);

你真正的意思是

widgetsLeftS1W1 = widgetsLeftS1W1 - (widgetStore1-numberSoldFirst1);

计算机不知道widgetsLeftS1W1的值,因此会出现错误。


结论:使用

widgetsLeftS1W1 = (widgetStore1 - numberSoldFirst1); 

尝试初始化的值

widgetsLeftS1W1
widgetsLeftS1W2
widgetsLeftS2W1
widgetsLeftS2W2

声明为顶部时为零。

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