[英]How do I clear this error?
我正在使用Java,并且我的程序应要求用户输入数字1-10。 如果数字不在护林员中,则它会显示一条错误消息。 还应该在拼云中显示所选的号码。 我的错误来自整数编号= keyboard.nextInt();
这是我其余的代码:
import java.util.Scanner;
public class ForReal {
public static void main(String[] args) {
int number;
Scanner keyboard = new Scanner(System.in);
System.out.println("enter an number");
int number = keyboard.nextInt();
while (number < 1 || number > 10)
System.out.print("Error, choose a number between 1-10");
switch (number)
{
case 1 : System.out.println("The English numberal 1" + number + " converts to the pinyin numeral yil1");
break;
case 2: System.out.println("The English numeral 2" + number + " converts to the pinyin numeral er4");
break;
case 3: System.out.println("The English numeral 3" + number + " converts to the pinyin numeral san1");
break;
case 4: System.out.println("The English numeral 4" + number + " converts to the pinyin numeral si4");
break;
case 5: System.out.println("The English numeral 5" + number + " converts to the pinyin numeral wu3");
break;
case 6: System.out.println("The English numeral 6" + number + " converts to the pinyin numeral liu4");
break;
case 7: System.out.println("The English numeral 7" + number + " converts to the pinyin numeral qil");
break;
case 8: System.out.println("The English numeral 8" + number + " converts to the pinyin numeral bal");
break;
case 9: System.out.println("The Arabic numeral 9" + number + " converts to the pinyin numeral jiu3");
break;
case 10: System.out.println("The Arabic numeral 10" + number + " converts to the pinyin numeral shi2");
break;
}
}
}
您要重新声明number
两次。 摆脱顶部的第一个声明。 这个:
int number;
您正在尝试定义两次int
数。
删除第一个声明或更改行:
int number = keyboard.nextInt();
与
number = keyboard.nextInt();
您可能还希望将调用包装在try and catch中,以检查是否有来自Scanner.nextInt()方法的预期异常。
int number = keyboard.nextInt();
while (number < 1 || number > 10)
System.out.print("Error, choose a number between 1-10");
这将行不通:它将永远打印消息,因为数字值在此循环内没有改变。
好,首先
我的错误来自整数编号= keyboard.nextInt();
好吧,很高兴知道您在哪一行上遇到错误,但是哪种错误会更好,只需将错误消息复制到问题中,可能variable number is already defined
或类似的东西
这行可能还会出现另一个错误,如果您输入的不是整数, InputMismatchException
可能会引发InputMismatchException
while (number < 1 || number > 10)
System.out.print("Error, choose a number between 1-10");
这不会更改number的值,请更改为
while (number < 1 || number > 10) {
System.out.print("Error, choose a number between 1-10");
number = keyboard.nextInt();
}
最后:
case 1 : System.out.println("The English numberal 1" + number + " converts to the pinyin numeral yil1");
break;
认真吗 编程是懒惰的人的发明者,因此可以告诉计算机让他们工作,尽管可以进行这种编程,但要避免这种重复(在更多地方使用相同的代码)。
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