我过度查询我的MySql数据库。 另一种检索许多数据的方法？

Question

我有这个表结构，我正在检索具有许多查询的数据。

• http://i.stack.imgur.com/q1Zjm.png

这是我如何查询数据库。

$siteurl = mysql_query("SELECT option_value FROM main_conf WHERE option_name = 'siteurl' ");
$_siteurl = mysql_result($siteurl,0);


$staticurl = mysql_query("SELECT option_value FROM main_conf WHERE option_name = 'staticurl' ");
$staticurl = mysql_result($staticurl,0);


$sitetitle = mysql_query("SELECT option_value FROM main_conf WHERE option_name = 'sitetitle' ");
$_sitetitle = mysql_result($sitetitle,0);


$sitesubtitle = mysql_query("SELECT option_value FROM main_conf WHERE option_name = 'sitesubtitle' ");
$_sitesubtitle = mysql_result($sitesubtitle,0);

$logofile = mysql_query("SELECT option_value FROM main_conf WHERE option_name = 'logofile' ");
$_logofile = mysql_result($logofile,0);

$cat1 = mysql_query("SELECT option_value FROM main_conf WHERE option_name = 'cat1' ");
$_cat1 = mysql_result($cat1,0);

$cat2 = mysql_query("SELECT option_value FROM main_conf WHERE option_name = 'cat2' ");
$_cat2 = mysql_result($cat2,0);

echo $_siteurl;

echo $_staticurl;

echo $_sitetitle;

echo $_sitesubtitle;

echo $_logofile;

echo $_cat1;

echo $_cat2;

还有另一种方法吗？

谢谢！

Answer 1

您可能会发现在一行中获取结果最简单。 您可以使用聚合在SQL中执行此操作：

SELECT max(case when option_name = 'siteurl' then option_value end) as siteurl,
       max(case when option_name = 'sitetitle' then option_value end) as sitetitle,
       max(case when option_name = 'sitesubtitle' then option_value end) as sitesubtitle,
       max(case when option_name = 'logofile' then option_value end) as logofile,
       max(case when option_name = 'cat1' then option_value end) as cat1,
       max(case when option_name = 'cat2' then option_value end) as cat2
FROM main_conf
WHERE option_name in ('siteurl', 'sitetitle', 'sitesubtitle', 'logofile', 'cat1', 'cat2');

结果将是一行，包含六列，每列一个。

Answer 2

戈登，我做了功课。 ：d

..这是完整的代码。

<?php

SELECT max(case when option_name = 'siteurl' then option_value end) as siteurl,
       max(case when option_name = 'sitetitle' then option_value end) as sitetitle,
       max(case when option_name = 'sitesubtitle' then option_value end) as sitesubtitle,
       max(case when option_name = 'logofile' then option_value end) as logofile,
       max(case when option_name = 'cat1' then option_value end) as cat1,
       max(case when option_name = 'cat2' then option_value end) as cat2
FROM main_conf
WHERE option_name in ('siteurl', 'sitetitle', 'sitesubtitle', 'logofile', 'cat1',    'cat2');

//this is my homework, the php part of the problem

$siteurl = mysql_result($query_from_main_conf, 0, 0);
$staticurl = mysql_result($query_from_main_conf, 0, 1);
$sitetitle = mysql_result($query_from_main_conf, 0, 2);
$sitesubtitle = mysql_result($query_from_main_conf, 0, 3);
$logofile = mysql_result($query_from_main_conf, 0, 4);
$cat1 = mysql_result($query_from_main_conf, 0, 5);
$cat2 = mysql_result($query_from_main_conf, 0, 6);

?>

然后，我使用ECHO检索了内容。

即

<?php echo $cat1; ?>

谢谢！！