neo4j密码，收集时返回字段而不是节点

Question

给定以下查询

match (a)-->(b)-->(c)
where id(a) = 0
return b.name, collect(c) as cs

如何返回仅由几个字段而不是整个节点组成的集合？

Answer 1

一个字段很容易：

match (a)-->(b)-->(c)
where id(a) = 0
return b.name, collect(c.fieldName) as cs

对于多个字段名称，也许将它们串联起来？

match (a)-->(b)-->(c)
where id(a) = 0
return b.name, collect(c.fieldName1 + delimiter + c.fieldName2) as cs

Answer 2

match (a)-->(b)-->(c)
where id(a) = 0
return b.name, collect( { field1: c.field1, field2: c.field2 } ) as cs