将动态列表转换为数据表c#

Question

正在搜索并破解我的大脑如何将动态列表转换为databale，c＃，请指教，谢谢

List<dynamic>dlist=new List<dynamic>

至

DataTable 

Answer 1

我觉得你看起来像这样。 希望它对你有用。

从动态列表到数据表：

   List<dynamic> dlist=new List<dynamic> 
   var json = JsonConvert.SerializeObject(dlist);
   DataTable dataTable = (DataTable)JsonConvert.DeserializeObject(json, (typeof(DataTable)));

还要从 DataTable 中获取 JsonString：

string JSONresult = JsonConvert.SerializeObject(dataTable);

Answer 2

以下是您可以将任何列表对象转换为数据表的方法。

 public DataTable ConvertToDataTable<T>(IList<T> data)
    {
        PropertyDescriptorCollection properties =
           TypeDescriptor.GetProperties(typeof(T));
        DataTable table = new DataTable();
        foreach (PropertyDescriptor prop in properties)
            table.Columns.Add(prop.Name, Nullable.GetUnderlyingType(prop.PropertyType) ?? prop.PropertyType);
        foreach (T item in data)
        {
            DataRow row = table.NewRow();
            foreach (PropertyDescriptor prop in properties)
                row[prop.Name] = prop.GetValue(item) ?? DBNull.Value;
            table.Rows.Add(row);
        }
        return table;

    }

http://social.msdn.microsoft.com/Forums/vstudio/en-US/6ffcb247-77fb-40b4-bcba-08ba377ab9db/converting-a-list-to-datatable?forum=csharpgeneral

Answer 3

 public DataTable ToDataTable<T>(dynamic items)
    {

        DataTable dtDataTable = new DataTable();
        if (items.Count == 0) return dtDataTable;

        ((IEnumerable)items[0]).Cast<dynamic>().Select(p => p.Name).ToList().ForEach(col => { dtDataTable.Columns.Add(col); });

        ((IEnumerable)items).Cast<dynamic>().ToList().
            ForEach(data =>
            {
                DataRow dr = dtDataTable.NewRow();
                ((IEnumerable)data).Cast<dynamic>().ToList().ForEach(Col => { dr[Col.Name] = Col.Value; });
                dtDataTable.Rows.Add(dr);
            });
        return dtDataTable;
    }

Answer 4

我不知道你为什么需要这个，但是，你可以使用这个ObjectShredder使用反射，它可以将任何东西转换为DataTable ，所以甚至是动态或匿名类型：

在泛型类型T不是DataRow的情况下实现CopyToDataTable<T>

但是，我的建议是不要命名该扩展方法CopyToDataTable ，而是例如CopyAnyToDataTable以避免与现有扩展方法CopyToDataTable发生冲突。

Answer 5

使用这个功能，

public static DataTable ConvertToDatatable<T>(this IList<T> data)
{
    PropertyDescriptorCollection props =
        TypeDescriptor.GetProperties(typeof(T));
    DataTable table = new DataTable();
    for(int i = 0 ; i < props.Count ; i++)
    {
        PropertyDescriptor prop = props[i];
        table.Columns.Add(prop.Name, prop.PropertyType);
    }
    object[] values = new object[props.Count];
    foreach (T item in data)
    {
        for (int i = 0; i < values.Length; i++)
        {
            values[i] = props[i].GetValue(item);
        }
        table.Rows.Add(values);
    }
    return table;        
    }

Answer 6

如果基础类型是 ExpandoObject，那么您需要检查 IDictionary 而不是通过反射。 希望这对将来的其他人有所帮助：

    public static DataTable ConvertToDataTable<T>(IEnumerable<T> data)
    {
        DataTable table = new DataTable();
        foreach (T item in data)
        {
            if (item is IDictionary<string, object> dict)
            {
                foreach (var key in dict)
                {
                    table.Columns.Add(key.Key, key.Value?.GetType() ?? typeof(object));
                }
                break;
            }
            foreach (var prop in typeof(T).GetProperties())
            {
                table.Columns.Add(prop.Name, prop.PropertyType);
            }
            break;
        }

        DataRow row = null;
        foreach (T item in data)
        {
            if (item is IDictionary<string, object> dict)
            {
                row = table.NewRow();
                foreach (var key in dict)
                {
                    row[key.Key] = key.Value;
                }
                table.Rows.Add(row);
                continue;
            }

            row = table.NewRow();
            foreach (var prop in typeof(T).GetProperties())
            {
                row[prop.Name] = prop.GetValue(item);
            }
            table.Rows.Add(row);
        }
        return table;
    }

Answer 7

使用 C# 将动态列表对象转换为 DataTable

 public DataTable DynamicToDT(List<object> objects)
        {
            DataTable dt = new DataTable("StudyRecords"); // Runtime Datatable          
            string[] arr = { "Name", "Department", "CollegeName", "Address" };// Column Name for DataTable
            if (objects != null && objects.Count > 0)
            {
                for (int i = 0; i < objects.Count; i++)
                {
                    dt.Columns.Add(arr[i]);
                    if (i == 0)
                    {
                        var items = objects[0] as IEnumerable<string>;
                        foreach (var itm in items)
                        {
                            DataRow dr1 = dt.NewRow(); // Adding values to Datatable  
                            dr1[arr[i]] = itm;
                            dt.Rows.Add(dr1);
                        }
                    }
                    else
                    {
                        var items = objects[i] as IEnumerable<string>;
                        int count = 0;
                        foreach (var itm in items)
                        {
                            dt.Rows[count][arr[i]] = itm;
                            count++;
                        }
                    }
                }

                return dt; // Converted Dynamic list to Datatable  
            }
            return null;
        }

Answer 8

public static DataTable DynamicToDT(List objects)

    {
        var data = objects.ToArray();
        if (data.Count() == 0) return null;
        var dt = new DataTable();
        foreach (var key in ((IDictionary<string, object>)data[0]).Keys)
        {
            dt.Columns.Add(key);
        }
        foreach (var d in data)
        {
            dt.Rows.Add(((IDictionary<string, object>)d).Values.ToArray());
        }
        return dt;
    }

Answer 9

// Obtem a lista dinamica via chamada API
List<dynamic> resultado = ExecutaQuery(sql);

// converte a lista dinamica com o resultado em JSON
string json = JsonConvert.SerializeObject(resultado);

// converte o json em datatable
DataTable dataTable = (DataTable)JsonConvert.DeserializeObject(json, (typeof(DataTable)));