成功登录PHP后需要在组合框中显示用户名

Question

我想在组合框中成功登录后显示用户名。

<?php
$val = $_POST['applicant']?:'';

$sql = "SELECT username FROM `user` where password = '".$_SESSION['password']."'";
$res = mysql_query($sql);
while ($row1 = mysql_fetch_array($res)) {
    $selected = ($val == $row1['username'] ? 'selected="selected"' : '');
    echo '<option value ="' . $row1['username'] . '" '. $selected .'>' . $row1['username'] . '</option>';

}
?>

Answer 1

尝试这个

$val = "";
if(isset($_POST['applicant']))
{
  $val = $_POST['applicant'];
}

$sql = "SELECT username FROM `user` where password = '".$_SESSION['password']."'";
$res = mysql_query($sql);
while ($row1 = mysql_fetch_array($res)) {
    $selected = ($val == $row1['username']) ? 'selected="selected"' : '';
    echo '<option value ="' . $row1['username'] . '" '. $selected .'>' . $row1['username'] . '</option>';

更新

更新still no result评论

您可以使用修剪发布值，并在表user中是否存在数据库中存在的username manualy列中进行检查

 $val = "";
    if(isset($_POST['applicant']))
    {
      $val = trim($_POST['applicant']);
    }
echo $val;


}