如果满足条件，则为MYSQL行数

Question

抱歉，但我不确定如何表达此问题或是否可行，但基本上我正在使用select语句，在该语句中，我想显示一列，该列显示满足条件的时间。 例如

SELECT pageID, isHome, if(ishome = 1, 'count?', 0) AS Passed
FROM pages

我希望passed列显示这样的运行计数

PageID | ishome | passed
10031  | 0      | 0
10032  | 1      | 1
10033  | 1      | 2
10034  | 1      | 3

感谢您的任何帮助

Answer 1

尝试以下操作（未经测试）

select a.pageid, a.ishome, sum(b.ishome) passed 
from 
pages a join pages b
on a.pageid>= b.pageid
group by a.pageid, a.ishome
order by a.pageid

Answer 2

    SELECT pageID, isHome,  count(*)  AS Passed 
    FROM pages
    where ishome = 1
    GROUP BY PageID 

DEMO

如果要显示所有结果，请使用此

 SELECT pageID, isHome,  if(ishome = 1, count(*), 0)  AS Passed 
 FROM pages
 group by pageID,ishome ;

DEMO

Answer 3

不确定，但我认为这是您想要的。

SELECT pageID, isHome, 
case when(ishome = 1)
  then count(*)
  else 0
end Passed FROM Table1
group by pageID;

sqlfiddle

或者，如果您想要传递的页面数

SELECT isHome, 
case when(ishome = 1)
  then count(*)
  else 0
end Passed FROM Table1
group by isHome;

sqlfiddle

Answer 4

试试这个

SELECT pageID, isHome,
CASE isHome 
  WHEN 1 THEN SELECT COUNT(*) FROM pages p 
              WHERE p.isHome = 1 AND p.pageID <= pageID 
  ELSE 0 
END as passed
FROM pages
ORDER BY pageID ASC