Symfony2无法捕获ResourceNotFoundException

Question

我创建了一个服务，将uris转换为带参数的routenames
我正在尝试捕获ResourceNotFoundException而不是现有的uris但是获得500错误和异常

<?php

namespace OOOO\AdvertisingBundle\Utilities;

use Symfony\Component\Routing\Generator\UrlGeneratorInterface;
use Symfony\Component\Routing\Router;

class RouteConverter
{
    private $router;

    public function __construct(Router $router)
    {
        $this->router = $router;
    }

    public function uriToRoute($uri)
    {
        try {
            $matched = $this->router->match($uri);
        } catch (Exception $e) {

            return null;
        }
        $result['name'] = $matched['_route'];
        unset($matched['_route']);
        unset($matched['_controller']);
        $result['parameters'] = $matched;

        return $result;
    }

    public function generateRoute($name, $parameters)
    {
        try {
            $matched = $this->router->generate($name, $parameters, UrlGeneratorInterface::RELATIVE_PATH);
        } catch (Exception $e) {

            return null;
        }
        return $matched;
    }
}

Answer 1

尝试用ResourceNotFoundException替换Exception 。 并且不要忘记use声明：

<?php

namespace OOOO\AdvertisingBundle\Utilities;

use Symfony\Component\Routing\Generator\UrlGeneratorInterface;
use Symfony\Component\Routing\Router;
use Symfony\Component\Routing\Exception\ResourceNotFoundException;

class RouteConverter
{
    private $router;

    public function __construct(Router $router)
    {
        $this->router = $router;
    }

    public function uriToRoute($uri)
    {
        try {
            $matched = $this->router->match($uri);
        } catch (ResourceNotFoundException $e) {

            return null;
        }
        $result['name'] = $matched['_route'];
        unset($matched['_route']);
        unset($matched['_controller']);
        $result['parameters'] = $matched;

        return $result;
    }

    public function generateRoute($name, $parameters)
    {
        try {
            $matched = $this->router->generate($name, $parameters, UrlGeneratorInterface::RELATIVE_PATH);
        } catch (ResourceNotFoundException $e) {

            return null;
        }
        return $matched;
    }
}

或者如果你想使用Exception ，不要忘记Symfony中名字之前的斜杠：

<?php

namespace OOOO\AdvertisingBundle\Utilities;

use Symfony\Component\Routing\Generator\UrlGeneratorInterface;
use Symfony\Component\Routing\Router;
use Symfony\Component\Routing\Exception\ResourceNotFoundException;

class RouteConverter
{
    private $router;

    public function __construct(Router $router)
    {
        $this->router = $router;
    }

    public function uriToRoute($uri)
    {
        try {
            $matched = $this->router->match($uri);
        } catch (\Exception $e) {

            return null;
        }
        $result['name'] = $matched['_route'];
        unset($matched['_route']);
        unset($matched['_controller']);
        $result['parameters'] = $matched;

        return $result;
    }

    public function generateRoute($name, $parameters)
    {
        try {
            $matched = $this->router->generate($name, $parameters, UrlGeneratorInterface::RELATIVE_PATH);
        } catch (\Exception $e) {

            return null;
        }
        return $matched;
    }
}