[英]Using cin.get() to discard unwanted characters from the input stream in c++
我正在为我的C ++类分配作业。 给出以下代码。 指导说明输入六个字符串并观察结果。 当我这样做时,第二个用户提示就会通过,程序结束。 我可以肯定的原因是,第一个cin.getline()在输入流中留下了多余的字符,这使第二个cin.getline()发生混乱。 我将使用cin.get,循环或同时使用两者,以防止多余的字符串字符干扰第二个cin.getline()函数。
有小费吗?
#include <iostream>
using namespace std;
int main()
{
char buffer[6];
cout << "Enter five character string: ";
cin.getline(buffer, 6);
cout << endl << endl;
cout << "The string you entered was " << buffer << endl;
cout << "Enter another five character string: ";
cin.getline(buffer, 6);
cout << endl << endl;
cout << "The string you entered was " << buffer << endl;
return 0;
}
你是对的。 第一次输入后,换行符保留在输入缓冲区中。
第一次阅读后,尝试插入:
cin.ignore(); // to ignore the newline character
还是更好:
//discards all input in the standard input stream up to and including the first newline.
cin.ignore(numeric_limits<streamsize>::max(), '\n');
为此,您必须#include <limits>
标头。
编辑:虽然使用std :: string会好得多,但以下修改后的代码有效:
#include <iostream>
#include <limits>
using namespace std;
int main()
{
char buffer[6];
cout << "Enter five character string: ";
for (int i = 0; i < 5; i++)
cin.get(buffer[i]);
buffer[5] = '\0';
cin.ignore(numeric_limits<streamsize>::max(), '\n');
cout << endl << endl;
cout << "The string you entered was " << buffer << endl;
cout << "Enter another five character string: ";
for (int i = 0; i < 5; i++)
cin.get(buffer[i]);
buffer[5] = '\0';
cin.ignore(numeric_limits<streamsize>::max(), '\n');
cout << endl << endl;
cout << "The string you entered was " << buffer << endl;
return 0;
}
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