将 Json 字符串转换为 C# Object 列表

Question

我想将 json 字符串转换为 Object 列表。 请帮我。 如果由NewtonJson完成会更有帮助。

我试过了，但它不起作用。 我不想要那个 json 的所有值。只是 MatrixModel 中提到的那些

这是一个 Object

public class MatrixModel
{
    public string S1 { get; set; }
    public string S2 { get; set; }
    public string S3 { get; set; }
    public string S4 { get; set; }
    public string S5 { get; set; }
    public string S6 { get; set; }
    public string S7 { get; set; }
    public string S8 { get; set; }
    public string S9 { get; set; }
    public string S10 { get; set; }
    public int ScoreIfNoMatch { get; set; }
}

这是 Json 字符串

    "[
      {
        "Question": {
          "QuestionId": 49,
          "QuestionText": "Whats your name?",
          "TypeId": 1,
          "TypeName": "MCQ",
          "Model": {
            "options": [
              {
                "text": "Rahul",
                "selectedMarks": "0"
              },
              {
                "text": "Pratik",
                "selectedMarks": "9"
              },
              {
                "text": "Rohit",
                "selectedMarks": "0"
              }
            ],
            "maxOptions": 10,
            "minOptions": 0,
            "isAnswerRequired": true,
            "selectedOption": "1",
            "answerText": "",
            "isRangeType": false,
            "from": "",
            "to": "",
            "mins": "02",
            "secs": "04"
          }
        },
        "CheckType": "",
        "S1": "",
        "S2": "",
        "S3": "",
        "S4": "",
        "S5": "",
        "S6": "",
        "S7": "",
        "S8": "",
        "S9": "Pratik",
        "S10": "",
        "ScoreIfNoMatch": "2"
      },
      {
        "Question": {
          "QuestionId": 51,
          "QuestionText": "Are you smart?",
          "TypeId": 3,
          "TypeName": "True-False",
          "Model": {
            "options": [
              {
                "text": "True",
                "selectedMarks": "7"
              },
              {
                "text": "False",
                "selectedMarks": "0"
              }
            ],
            "maxOptions": 10,
            "minOptions": 0,
            "isAnswerRequired": false,
            "selectedOption": "3",
            "answerText": "",
            "isRangeType": false,
            "from": "",
            "to": "",
            "mins": "01",
            "secs": "04"
          }
        },
        "CheckType": "",
        "S1": "",
        "S2": "",
        "S3": "",
        "S4": "",
        "S5": "",
        "S6": "",
        "S7": "True",
        "S8": "",
        "S9": "",
        "S10": "",
        "ScoreIfNoMatch": "2"
      }
    ]"

Answer 1

您可以使用json2csharp.com将您的 json 转换为对象模型

• 转到json2csharp.com
• 将您的 JSON 放入框中。
• 点击生成。
• 您将获得对象模型的 C# 代码
• 反序列化var model = JsonConvert.DeserializeObject<RootObject>(json); 使用牛顿

在这里，它将生成如下内容：

public class MatrixModel
{
    public class Option
    {
        public string text { get; set; }
        public string selectedMarks { get; set; }
    }

    public class Model
    {
        public List<Option> options { get; set; }
        public int maxOptions { get; set; }
        public int minOptions { get; set; }
        public bool isAnswerRequired { get; set; }
        public string selectedOption { get; set; }
        public string answerText { get; set; }
        public bool isRangeType { get; set; }
        public string from { get; set; }
        public string to { get; set; }
        public string mins { get; set; }
        public string secs { get; set; }
    }

    public class Question
    {
        public int QuestionId { get; set; }
        public string QuestionText { get; set; }
        public int TypeId { get; set; }
        public string TypeName { get; set; }
        public Model Model { get; set; }
    }

    public class RootObject
    {
        public Question Question { get; set; }
        public string CheckType { get; set; }
        public string S1 { get; set; }
        public string S2 { get; set; }
        public string S3 { get; set; }
        public string S4 { get; set; }
        public string S5 { get; set; }
        public string S6 { get; set; }
        public string S7 { get; set; }
        public string S8 { get; set; }
        public string S9 { get; set; }
        public string S10 { get; set; }
        public string ScoreIfNoMatch { get; set; }
    }
}

然后你可以反序列化为：

var model = JsonConvert.DeserializeObject<List<MatrixModel.RootObject>>(json);

Answer 2

public static class Helper
{
    public static string AsJsonList<T>(List<T> tt)
    {
        return new JavaScriptSerializer().Serialize(tt);
    }
    public static string AsJson<T>(T t)
    {
        return new JavaScriptSerializer().Serialize(t);
    }
    public static List<T> AsObjectList<T>(string tt)
    {
        return new JavaScriptSerializer().Deserialize<List<T>>(tt);
    }
    public static T AsObject<T>(string t)
    {
        return new JavaScriptSerializer().Deserialize<T>(t);
    }
}

Answer 3

请确保所有属性都是 getter 和 setter。 如果任何属性只是 getter，它将导致在键入 JSON 字符串时将 List 恢复为原始数据。

请参考以下相同的代码片段：型号：

 public class Person
{
    public int ID { get; set; }
    // following 2 lines are cause of error
    //public string Name { get { return string.Format("{0} {1}", First, Last); } }
    //public string Country { get { return Countries[CountryID]; } }
    public int CountryID { get; set; }
    public bool Active { get; set; }
    public string First { get; set; }
    public string Last { get; set; }
    public DateTime Hired { get; set; }
}
public class ModelObj
    {
        public string Str { get; set; }
        public List<Person> Persons { get; set; }
    }

控制器：

 [HttpPost]
    public ActionResult Index(FormCollection collection)
    {
        var data = new ModelObj();
        data.Str = (string)collection.GetValue("Str").ConvertTo(typeof(string));
        var personsString = (string)collection.GetValue("Persons").ConvertTo(typeof(string));
        using (var textReader = new StringReader(personsString))
        {
            using (var reader = new JsonTextReader(textReader))
            {
                data.Persons = new JsonSerializer().Deserialize(reader, typeof(List<Person>)) as List<Person>; 
            }
        }

        return View(data);
    }

Answer 4

在 C# 中使用动态变量是最简单的。

Newtonsoft.Json.Linq 具有可以使用的 JValue 类。 下面是一个示例代码，它显示您拥有的 JSON 字符串中的问题 ID 和文本。

        string jsonString = "[{\"Question\":{\"QuestionId\":49,\"QuestionText\":\"Whats your name?\",\"TypeId\":1,\"TypeName\":\"MCQ\",\"Model\":{\"options\":[{\"text\":\"Rahul\",\"selectedMarks\":\"0\"},{\"text\":\"Pratik\",\"selectedMarks\":\"9\"},{\"text\":\"Rohit\",\"selectedMarks\":\"0\"}],\"maxOptions\":10,\"minOptions\":0,\"isAnswerRequired\":true,\"selectedOption\":\"1\",\"answerText\":\"\",\"isRangeType\":false,\"from\":\"\",\"to\":\"\",\"mins\":\"02\",\"secs\":\"04\"}},\"CheckType\":\"\",\"S1\":\"\",\"S2\":\"\",\"S3\":\"\",\"S4\":\"\",\"S5\":\"\",\"S6\":\"\",\"S7\":\"\",\"S8\":\"\",\"S9\":\"Pratik\",\"S10\":\"\",\"ScoreIfNoMatch\":\"2\"},{\"Question\":{\"QuestionId\":51,\"QuestionText\":\"Are you smart?\",\"TypeId\":3,\"TypeName\":\"True-False\",\"Model\":{\"options\":[{\"text\":\"True\",\"selectedMarks\":\"7\"},{\"text\":\"False\",\"selectedMarks\":\"0\"}],\"maxOptions\":10,\"minOptions\":0,\"isAnswerRequired\":false,\"selectedOption\":\"3\",\"answerText\":\"\",\"isRangeType\":false,\"from\":\"\",\"to\":\"\",\"mins\":\"01\",\"secs\":\"04\"}},\"CheckType\":\"\",\"S1\":\"\",\"S2\":\"\",\"S3\":\"\",\"S4\":\"\",\"S5\":\"\",\"S6\":\"\",\"S7\":\"True\",\"S8\":\"\",\"S9\":\"\",\"S10\":\"\",\"ScoreIfNoMatch\":\"2\"}]";
        dynamic myObject = JValue.Parse(jsonString);
        foreach (dynamic questions in myObject)
        {
            Console.WriteLine(questions.Question.QuestionId + "." + questions.Question.QuestionText.ToString());
        }
        Console.Read();

代码输出 =>

Answer 5

如果没有明确需要 class（型号），您也可以使用动态

List<dynamic> models = JsonConvert.DeserializeObject<List<dynamic>>(jsonString);

然后使用点访问您需要的任何字段

models[0].MyField

Answer 6

尝试更改 ScoreIfNoMatch 的类型，如下所示：

   public class MatrixModel
        {
            public string S1 { get; set; }
            public string S2 { get; set; }
            public string S3 { get; set; }
            public string S4 { get; set; }
            public string S5 { get; set; }
            public string S6 { get; set; }
            public string S7 { get; set; }
            public string S8 { get; set; }
            public string S9 { get; set; }
            public string S10 { get; set; }
            // the type should be string
            public string ScoreIfNoMatch { get; set; }
        }

Answer 7

class定义中的变量/参数需要{ get; set; } { get; set; } { get; set; }我用像一个变量声明（愚蠢的我，因为它是在为其他场景）无

{ get; set; }

因此，无论我从 JavaScript 发送什么，都不会在 Action 方法中接收到。 它总是得到 null 或空模型。

一旦{get; set;} 被添加，它就像魅力一样工作。

我希望它可以帮助那些来自 VB6 编程风格的人。