[英]Read from file inside Eclipse Project
我想创建一个将inputfolder
内的大文本文件inputfolder
为几个小XML文件以放入outputfolder
内的应用outputfolder
。
这是项目大纲:
从外部文件夹获取文件时,以下代码可以正常工作,但是当我将其修改为从项目内部的文件夹中读取文件时,它给了我这个错误:
Exception in thread "main" java.lang.NullPointerException
at com.zakaria.cut.XmlCutter.cut(XmlCutter.java:45)
at com.zakaria.cut.Main.main(Main.java:8)
[XmlCutter.java]
package com.zakaria.cut;
import java.io.BufferedReader;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.text.MessageFormat;
import java.util.logging.ConsoleHandler;
import java.util.logging.Handler;
import java.util.logging.Level;
import java.util.logging.Logger;
public class XmlCutter {
private static final String OUTPUT_FILE_NAME = "/file";
//private static String USER_HOME = System.getProperty("user.home");
private static final String INPUT_FOLDER = "../inputfolder";
private static String OUTPUT_FOLDER = "../outputfolder";
private static Logger LOG = Logger.getLogger("XmlCutter");
private static long COUNTER = 0;
public XmlCutter() {
super();
// TODO Auto-generated constructor stub
}
public void cut() {
Handler h = new ConsoleHandler();
h.setLevel(Level.FINE);
LOG.addHandler(h);
LOG.setLevel(Level.FINE);
File inputDir = new File(INPUT_FOLDER);
File[] filesInInputDir = inputDir.listFiles();
for (File f : filesInInputDir) {
if ((f.getName()).endsWith(".txt")) {
LOG.fine((MessageFormat.format(
"Found a text file {0}. Processing docs...",
f.getName())));
processFile(f);
}
}
}
private static void processFile(File f) {
StringBuilder out = new StringBuilder();
char prev = '#';
try {
BufferedReader br = new BufferedReader(new InputStreamReader(
new FileInputStream(f), "UTF8"));
char[] buf = new char[1];
while (br.read(buf) >= 0) {
out.append(buf[0]);
if (prev == '<' && buf[0] == '?') {
LOG.finest((MessageFormat.format(
"Start of XML PI Found: {0}{1}", prev, buf[0])));
if (out.length() > 2) {
flushToFile(out.substring(0, out.length() - 2));
}
out.setLength(2);
}
prev = buf[0];
}
LOG.finest("Writing final file");
flushToFile(out.toString());
br.close();
} catch (IOException e) {
LOG.fine(e.getMessage());
}
LOG.fine(MessageFormat.format("Generated {0} XML Documents", COUNTER));
}
private static void flushToFile(String s) {
File f = new File(OUTPUT_FOLDER + OUTPUT_FILE_NAME + (++COUNTER)
+ ".xml");
LOG.finest(MessageFormat.format("Writing file: {0}", f.getName()));
try {
FileOutputStream fos = new FileOutputStream(f);
OutputStreamWriter osw = new OutputStreamWriter(fos, "UTF8");
osw.write(s);
osw.flush();
} catch (IOException e) {
LOG.fine(e.getMessage());
}
}
}
[Main.java]
package com.zakaria.cut;
public class Main {
public static void main(String[] args) {
XmlCutter cutter = new XmlCutter();
cutter.cut();
}
}
我想问题肯定在这里:
private static final String INPUT_FOLDER = "../inputfolder";
private static String OUTPUT_FOLDER = "../outputfolder";
我该如何解决?
您知道程序从哪个文件夹执行吗? 我的猜测是相对链接指向了错误的位置? 您是否尝试过硬编码路径,看看它们是否有效? 如果这样做,您可能必须查看执行文件夹,然后相应地更改相对路径?
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