[英]Embed form into another form linked to entity in Symfony2
我需要将一种形式嵌入另一种形式中,我正在做如下工作:
use Symfony\Component\Form\AbstractType,
Symfony\Component\Form\FormBuilderInterface,
Symfony\Component\OptionsResolver\OptionsResolverInterface,
Common\CommonBundle\Form\AddressExtraInfoType;
class StandardAddressType extends AbstractType {
public function buildForm(FormBuilderInterface $builder, array $options) {
$builder
->add('country', 'entity', array( ... ))
->add('state', 'entity', array( ... ))
->add('city', 'entity', array( ... ))
->add('extra_info', new AddressExtraInfoType());
}
public function setDefaultOptions(OptionsResolverInterface $resolver) {
$resolver->setDefaults(array(
'data_class' => 'Common\CommonBundle\Entity\StandardAddress'
));
}
public function getName() {
return 'common_commonbundle_standard_address';
}
}
由于主表单需要附加到'data_class' => 'Common\\CommonBundle\\Entity\\StandardAddress'
所以当我尝试获取表单时会出现此错误:
Neither the property "extra_info" nor one of the methods "getExtraInfo()", "isExtraInfo()", "hasExtraInfo()", "__get()" exist and have public access in class "Common\CommonBundle\Entity\StandardAddress"
我该如何解决? 如何在不弄错的情况下将第二种形式嵌入第一种形式?
尝试这个:
$builder->add('extra_info', new AddressExtraInfoType(), array('mapped' => false));
in class so you must use non mapped field in form type 您在类没有字段 ,因此您必须使用表单类型的非映射字段
最后,再次阅读我的代码后,我发现了错误所在。 在我的AddressExtraInfo
实体中,我有address_extra_info
,当然可以将其更改为extra_info
解决此问题,无论如何,感谢您的答复
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