[英]Retrieve multiple data from Array
几个月前我问了这个问题,但是那时我只需要提取一个会员级别,现在我需要提取每个级别的名称,这是数组:
Array
(
[success] => 1
[member] => Array
(
[0] => Array
(
[Levels] => Array
(
[1391447566] => stdClass Object
(
[Level_ID] => 1391447566
[Name] => Team Membership
[Cancelled] =>
[CancelDate] =>
[Pending] =>
[UnConfirmed] =>
[Expired] =>
ExpiryDate] => 1397266537
[SequentialCancelled] =>
[Active] => 1
[Status] => Array
(
[0] => Active
)
[Timestamp] => 1394588137
[TxnID] => WL-1-1391447566
)
[1391540448] => stdClass Object
(
[Level_ID] => 1391540448
[Name] => Gold Training Membership
[Cancelled] =>
[CancelDate] =>
[Pending] =>
[UnConfirmed] =>
[Expired] =>
[ExpiryDate] => 1396642789
[SequentialCancelled] =>
[Active] => 1
[Status] => Array
(
[0] => Active
)
[Timestamp] => 1393967989
[TxnID] => WL-1-1391540448
)
[1391540567] => stdClass Object
(
[Level_ID] => 1391540567
[Name] => Platinum Training Membership
[Cancelled] =>
[CancelDate] =>
[Pending] =>
[UnConfirmed] =>
[Expired] =>
[ExpiryDate] => 1397302237
[SequentialCancelled] =>
[Active] => 1
[Status] => Array
(
[0] => Active
)
[Timestamp] => 1394623837
[TxnID] => WL-1-1391540567
)
)
[PayPerPosts] => Array
(
)
)
)
[supported_verbs] => Array
(
[0] => GET
[1] => PUT
[2] => DELETE
)
)
我需要的是每次拉一个具有不同编号的对象内部的级别名称,并将其添加到我需要保存在数据库中的数组中。 一种用于获取信息的解决方案是浪费:
foreach ($response["member"][0]["Levels"] AS $level_key => $level_val) {
$level_name = $level_key->Name;
echo 'Name: '.$level_name;
}
但它没有拉动任何东西,只是回呼“名称” 3次。
这是我只提取一个名称的代码:
$levels = $response["member"][0]["Levels"];
$firstLevel = array_shift(array_values($levels));
$membership = $firstLevel->Name;
谢谢!
只需尝试:
$level_name = $level_val->Name;
$level_key
是具有级别ID(?)的整数值。 $level_val
是您的带有数据的关卡对象。
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