替换SQL Server XQuery中的空XML节点的值

Question

我尝试了以下方法，但没有找到一种方法来删除空节点值而不删除它并且不使用XML属性。

替换节点在MS-SQL中不可用。

DECLARE @doc xml
SET @doc = '
    <f1>1</f1> 
    <f2/>
'
print '1) ' + convert(varchar(4000),@doc)


SET @doc.modify('
    replace value of (/f1/text())[1]
        with (''v2'')
')
print '2) ' + convert(varchar(4000),@doc)


SET @doc.modify('
    replace value of (/f1/text())[1]
        with (''v3'')
')
print '3) ' + convert(varchar(4000),@doc)


SET @doc.modify('
    replace value of (/f2/text())[1]
        with (''v4'')
')
print '4) ' + convert(varchar(4000),@doc)   + ' did not replace f2 value'


begin try
    exec sp_executesql N'
        SET @doc.modify(''
                replace value of (/f2)[1] with (''''v5'''')
        '')
        print ''5) '' + convert(varchar(4000),@doc)
    ',N'@doc xml',@doc
end try begin catch
    print '5) ' + error_message()
end catch


begin try
    exec sp_executesql N'
        SET @doc.modify(''
            replace value of (/f2/node())[1]
                with (''''v6'''')
        '')
        print ''6) '' + convert(varchar(4000),@doc)
    ',N'@doc xml',@doc
end try begin catch
    print '6) ' + error_message()
end catch


begin try
    exec sp_executesql N'
        SET @doc.modify(''
            replace value of (/f2)[1]
                with (''''<f2>v7/f2>'''')
        '')
        print ''7) '' + convert(varchar(4000),@doc)
    ',N'@doc xml',@doc
end try begin catch
    print '7) ' + error_message()
end catch


SET @doc.modify('
    delete (/f2)
')
SET @doc.modify('
    insert <f2>v8</f2> as last
        into (.)[1]
')
print '8) ' + convert(varchar(4000),@doc) + ' only delete and add works'

/*
    output:
        1) <f1>1</f1><f2/>
        2) <f1>v2</f1><f2/>
        3) <f1>v3</f1><f2/>
        4) <f1>v3</f1><f2/> did not replace f2 value
        5) XQuery [modify()]: The target of 'replace value of' must be a non-metadata attribute or an element with simple typed content, found 'element(f2,xdt:untyped) ?'
        6) XQuery [modify()]: The target of 'replace value of' cannot be a union type, found '(element(*,xdt:untyped) | comment | processing-instruction | text) ?'.
        7) XQuery [modify()]: The target of 'replace value of' must be a non-metadata attribute or an element with simple typed content, found 'element(f2,xdt:untyped) ?'
        8) <f1>v3</f1><f2>v8</f2> only delete and add works
*/

Answer 1

好吧，我认为像这样的事情会做到的

DECLARE @doc xml
SET @doc = '
    <f1>1</f1> 
    <f2/>
'
print '1) ' + convert(varchar(4000),@doc)


SET @doc.modify('
    insert text{"v9"} into (/f2)[1]
')
print '2) ' + convert(varchar(4000),@doc)