C＃使用泛型打开表单？

Question

我有一个带有菜单的主窗体，该菜单包含很多项目，这些项目又打开了不同的窗体。 目前，我执行以下操作以打开特定表格：

        if (canShowCustomerForm)
            new CustomerForm().ShowDialog(this);
        else
        {
            MessageBox.Show("You don't have enough rights to view this form.");
        }

有没有一种方法可以在类中移动此代码，然后传递表单类型和布尔参数，而不是为每个菜单项重复代码？

Answer 1

public static class FormHelper
{
    public static DisplayResult ShowForm<T>(IWin32Window owner, bool canShowForm)
        where T : Form, new()
    {
        if (canShowForm)
        {
            using (T form = new T())
            {
                return form.ShowDialog(owner);
            }
        }
        else
        {
            MessageBox.Show("You don't have enough rights to view this form.");
        }
    }
}

Answer 2

您可以将其提取到如下所示的函数中，而不是一遍又一遍地编写相同的逻辑：

void ShowFormIfAllowed<TForm>(bool allowed) where TForm : Form, new() {
      if (allowed) {
          using (var form = new TForm()) {
               form.ShowDialog(this);
          }
      }
      else {
            MessageBox.Show("You don't have enough rights to view this form.");
      }
 }

然后，您可以在菜单处理中将其命名为：

ShowFormIfAllowed<CustomerForm>(canShowCustomerForm);