如何使用MySQL将数组插入php中的数据库？

Question

我的代码是：

<?php
include("connect.php");
mysql_select_db("cars",$conec);
car = array("BMW","Rolls-Royce","Lamborghini","Mustang");
color = array("red","green","blue","yellow"); 
?>

我想做的是将每辆车插入数据库，这是我尝试做的事，但是我得到的id却越来越多，因为它是自动递增的。 这是我的插入代码如下：

for($i = 0; $i < 4; $i++){
    $res = mysql_query("insert into auto (car,colors) values ('$car[$i]','$color[$i]')");
}

Answer 1

编辑

经过测试和工作

<?php
DEFINE ('DB_USER', 'xxx');
DEFINE ('DB_PASSWORD', 'xxx');  
DEFINE ('DB_HOST', 'xxx');
DEFINE ('DB_NAME', 'xxx');

$mysqli = @mysqli_connect (DB_HOST, DB_USER, DB_PASSWORD, DB_NAME) 
OR die("could not connect");

$car = array("BMW","Rolls-Royce","Lamborghini","Mustang");
$color = array("red","green","blue","yellow");

for($i = 0; $i < 4; $i++){
    $res = mysqli_query($mysqli,"insert into auto (car,colors) values ('$car[$i]','$color[$i]')");
}
?>

---

如果这是您发布的实际代码：

您忘记了car和color变量的$符号。

 car = array("BMW","Rolls-Royce","Lamborghini","Mustang");
^-- // here
 color = array("red","green","blue","yellow"); 
^-- // and here

---

<?php
include("connect.php");
mysql_select_db("cars",$conec);
$car = array("BMW","Rolls-Royce","Lamborghini","Mustang");
$color = array("red","green","blue","yellow"); 
?>

---

Answer 2

我认为将PHP数组放在MySQL中通常不被接受，因为它们只能被PHP读取。 你应该跑

$car = json_encode($car);
$color = json_encode($color);

然后，当您想从数据库中提取信息时运行

$car = json_decode($mysqlcarvarhere);
$color = json_decode($mysqlcolorvarhere);

另外，在第二段代码中，这会将'$ car [$ i]'插入数据库，而不是将$ car ['$ i']的值插入数据库。 要解决此问题，您应该将查询更改为：

$res = mysql_query("insert into auto (car,colors) values ('" . $car[$i] . "','" . $color[$i] ."')");

同样，在这里也有一般性的“您应该切换到PDO / MySQLi，否则您将被黑”。

Answer 3

出于各种原因 ，我建议您使用“ 准备的语句” 。

假设已经与数据库建立了连接，这是一种实现方法：

<?php
    include("connect.php");

    $cars = array("BMW","Rolls-Royce","Lamborghini","Mustang");
    $colors = array("red","green","blue","yellow"); 

    $db = new mysqli($host, $user, $password, $database);
    $stmt = $db->prepare("INSERT INTO auto(car, color) VALUES(?, ?)");

    // Here I deliberately assume that all car has every color variant
    foreach($cars as $car) {
        foreach($colors as $color) {
            $stmt->bind_param('s', $car);
            $stmt->bind_param('s', $color);

            $stmt->execute();
        }
    }

    $stmt->close();

?>

如何使用Prepared Statement解决它只是一个粗略的主意，您始终可以将其包装在一个函数或一个类中。