从一个表中选择多个列并将数据插入到 PHP-MySQL 中不同数据库中的另一个表中

Question

我必须从数据库中的表中选择数据并将它们插入到不同数据库中的另一个表中。 下面的代码返回$select_query OK，但$insert_query不正确。 您能否更正代码并让我知道您的回复？

$host1 = "localhost";
$user1 = "jackpot";
$pass1 = "jackpot";
$db1 = "pinkapple";
$host2 = "localhost";
$user2 = "jackpot";
$pass2 = "jackpot";
$db2 = "blueberry";

$mysql_connection1 = mysql_connect($host1, $user1, $pass1);
mysql_select_db($db1, $mysql_connection1) or die(mysql_error());
$select_query = mysql_query("SELECT field1, field2, field3 FROM tree WHERE date_entered > '2014-01-01 16:22:00'", $mysql_connection1);
$number = mysql_num_rows($select_query);

    if ($select_query) {
        echo "Select Query is OK <br>";
        echo $number ."<br>";
    } else {
        echo "Select Query is  not OK <br>";
    }

$mysql_connection2 = mysql_connect($host2, $user2, $pass2, true);

mysql_select_db($db2, $mysql_connection2) or die(mysql_error());

    while ($row = mysql_fetch_array($select_query)) {
    $field1 = $row['field1'];
    $field2 = $row['field2'];
    $field3 = $row['field3'];
    $insert_query = mysql_query("INSERT INTO jungle (desk1, chair1, table1) VALUES ('$field1', '$field2', '$field3')", $mysql_connection2);
        if ($insert_query) {
            echo "Insert Query is OK <br>";
        } else {
            echo "Insert Query is not OK <br>";
        }
}
mysql_close($mysql_connection1);
mysql_close($mysql_connection2);

下面你可以看到表格的示意图。

Answer 1

你需要建立的价值观？

"INSERT INTO jungle (desk1, chair1, table1) VALUES (value1, value2, value3)"

您应该从第一个选择中收集数据，然后您可以在插入语句中设置相关值

你可以使用mysql_fetch语句来做到这一点

$mysql_connection2 = mysql_connect($host2, $user2, $pass2, true);
mysql_select_db($db2, $mysql_connection2) or die(mysql_error());

while($row = mysql_fetch_array($select_query))
{
    $field1 = $row['field1'];
    $field2 = $row['field2'];
    $field3 = $row['field3'];
    $insert_query = mysql_query("INSERT INTO jungle (desk1, chair1, table1) VALUES ('$field1', '$field2', '$field3')",$mysql_connection2);

    if ($insert_query) {
      echo "Insert Query is OK <br>";
    } else {
      echo "Insert Query is not OK <br>";
    }

}

此语句遍历您的 select 语句，并使用INSERT语句为每个返回的结果插入一行

但实际上您也应该查看mysqli因为mysql已贬值。 然而，这是您正在做的事情背后的基本逻辑

Answer 2

为什么不尝试使用mysql Trigger，如果你在同一个mysql服务器上，我虽然比使用php更有效，你可以看到这个问题以获取更多信息

http://stackoverflow.com/questions/7128173/mysql-trigger-to-insert-data-into-different-db

和这里

http://stackoverflow.com/questions/20441783/mysql-create-trigger-insert-content-into-another-database

Answer 3

我知道帖子很旧，但我必须做同样的事情并按照建议使用 mysqli。 我唯一要注意的是这个例子只使用了一个整数字段和一个短文本字段。 如果您有其他字段，您应该使用准备好的语句，但是据我所知，这里的数据是固定的并且不包含特殊字符，所以这可以满足我的需要。

<?php
include "database1.php"; // Using database connection file here conn variable is $connj
include "database2.php"; // Using database connection file here conn variable is $conn
                    

// select data and put values in array from first database
                $selectsql = mysqli_query($connj,"SELECT id,name FROM table1 
                ORDER BY id ASC");
                $result = mysqli_query($connj, $selectsql);
                
                while($row = mysqli_fetch_array($selectsql))
                {
                    $id = $row['id'];
                    $name = $row['name'];
                    
//replace query into second table in second database    
                    $replacesql = mysqli_query($conn, "REPLACE INTO table2 (name,id) VALUES ('$name','$username','$id');");
                
                    if($replacesql) 
                        {                   
                        echo "Replace Successful<br>";
                        }
                    else 
                            {
                            echo "replace error<br>";
                            }
                }
?>